ASVAB Arithmetic Reasoning Practice Test 279701 Results

Your Results Global Average
Questions 5 5
Correct 0 2.65
Score 0% 53%

Review

1

Convert a-4 to remove the negative exponent.

68% Answer Correctly
\( \frac{-4}{-a} \)
\( \frac{-1}{-4a} \)
\( \frac{1}{a^4} \)
\( \frac{4}{a} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


2

What is 5\( \sqrt{3} \) x 3\( \sqrt{3} \)?

41% Answer Correctly
8\( \sqrt{3} \)
15\( \sqrt{3} \)
45
15\( \sqrt{6} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

5\( \sqrt{3} \) x 3\( \sqrt{3} \)
(5 x 3)\( \sqrt{3 \times 3} \)
15\( \sqrt{9} \)

Now we need to simplify the radical:

15\( \sqrt{9} \)
15\( \sqrt{3^2} \)
(15)(3)
45


3

What is \( 4 \)\( \sqrt{32} \) - \( 9 \)\( \sqrt{2} \)

38% Answer Correctly
36\( \sqrt{64} \)
-5\( \sqrt{32} \)
7\( \sqrt{2} \)
36\( \sqrt{32} \)

Solution

To subtract these radicals together their radicands must be the same:

4\( \sqrt{32} \) - 9\( \sqrt{2} \)
4\( \sqrt{16 \times 2} \) - 9\( \sqrt{2} \)
4\( \sqrt{4^2 \times 2} \) - 9\( \sqrt{2} \)
(4)(4)\( \sqrt{2} \) - 9\( \sqrt{2} \)
16\( \sqrt{2} \) - 9\( \sqrt{2} \)

Now that the radicands are identical, you can subtract them:

16\( \sqrt{2} \) - 9\( \sqrt{2} \)
(16 - 9)\( \sqrt{2} \)
7\( \sqrt{2} \)


4

What is x4 + 3x4?

66% Answer Correctly
4x-8
-2x-4
4x4
4x16

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

1x4 + 3x4
(1 + 3)x4
4x4


5

53% Answer Correctly
9.0
1
2.4
0.8

Solution


1