ASVAB Arithmetic Reasoning Practice Test 280669 Results

Your Results Global Average
Questions 5 5
Correct 0 3.43
Score 0% 69%

Review

1

Charlie loaned Roger $600 at an annual interest rate of 4%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$21
$4
$24
$39

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $600
i = 0.04 x $600
i = $24


2

Solve for \( \frac{3!}{4!} \)

67% Answer Correctly
72
\( \frac{1}{4} \)
\( \frac{1}{504} \)
5

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{4!} \)
\( \frac{3 \times 2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{1}{4} \)
\( \frac{1}{4} \)


3

If a rectangle is twice as long as it is wide and has a perimeter of 18 meters, what is the area of the rectangle?

47% Answer Correctly
72 m2
8 m2
50 m2
18 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 18 meters so the equation becomes: 2w + 2h = 18.

Putting these two equations together and solving for width (w):

2w + 2h = 18
w + h = \( \frac{18}{2} \)
w + h = 9
w = 9 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 9 - 2w
3w = 9
w = \( \frac{9}{3} \)
w = 3

Since h = 2w that makes h = (2 x 3) = 6 and the area = h x w = 3 x 6 = 18 m2


4

4! = ?

84% Answer Correctly

3 x 2 x 1

5 x 4 x 3 x 2 x 1

4 x 3

4 x 3 x 2 x 1


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


5

What is \( \frac{14\sqrt{14}}{7\sqrt{2}} \)?

71% Answer Correctly
2 \( \sqrt{\frac{1}{7}} \)
2 \( \sqrt{7} \)
\(\frac{1}{2}\) \( \sqrt{\frac{1}{7}} \)
7 \( \sqrt{2} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{14\sqrt{14}}{7\sqrt{2}} \)
\( \frac{14}{7} \) \( \sqrt{\frac{14}{2}} \)
2 \( \sqrt{7} \)