ASVAB Arithmetic Reasoning Practice Test 283010 Results

Your Results Global Average
Questions 5 5
Correct 0 2.94
Score 0% 59%

Review

1

Solve 5 + (5 + 3) ÷ 4 x 5 - 22

53% Answer Correctly
2
\(\frac{1}{2}\)
11
\(\frac{5}{7}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

5 + (5 + 3) ÷ 4 x 5 - 22
P: 5 + (8) ÷ 4 x 5 - 22
E: 5 + 8 ÷ 4 x 5 - 4
MD: 5 + \( \frac{8}{4} \) x 5 - 4
MD: 5 + \( \frac{40}{4} \) - 4
AS: \( \frac{20}{4} \) + \( \frac{40}{4} \) - 4
AS: \( \frac{60}{4} \) - 4
AS: \( \frac{60 - 16}{4} \)
\( \frac{44}{4} \)
11


2

Convert 2,867,000 to scientific notation.

62% Answer Correctly
0.287 x 107
28.67 x 105
2.867 x 10-5
2.867 x 106

Solution

A number in scientific notation has the format 0.000 x 10exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:

2,867,000 in scientific notation is 2.867 x 106


3

The total water usage for a city is 20,000 gallons each day. Of that total, 29% is for personal use and 40% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?

58% Answer Correctly
4,250
2,200
7,200
8,750

Solution

40% of the water consumption is industrial use and 29% is personal use so (40% - 29%) = 11% more water is used for industrial purposes. 20,000 gallons are consumed daily so industry consumes \( \frac{11}{100} \) x 20,000 gallons = 2,200 gallons.


4

How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 10 gallon tank to fill it exactly halfway?

52% Answer Correctly
2
4
3
7

Solution

To fill a 10 gallon tank exactly halfway you'll need 5 gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:

cans = \( \frac{5 \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 2


5

What is \( \sqrt{\frac{16}{9}} \)?

70% Answer Correctly
1\(\frac{1}{2}\)
1\(\frac{1}{3}\)
\(\frac{3}{5}\)
\(\frac{3}{4}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{16}{9}} \)
\( \frac{\sqrt{16}}{\sqrt{9}} \)
\( \frac{\sqrt{4^2}}{\sqrt{3^2}} \)
\( \frac{4}{3} \)
1\(\frac{1}{3}\)