ASVAB Arithmetic Reasoning Practice Test 283190 Results

Your Results Global Average
Questions 5 5
Correct 0 3.26
Score 0% 65%

Review

1

How many hours does it take a car to travel 100 miles at an average speed of 25 miles per hour?

86% Answer Correctly
7 hours
4 hours
1 hour
8 hours

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for time:

time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{100mi}{25mph} \)
4 hours


2

What is \( 8 \)\( \sqrt{50} \) - \( 5 \)\( \sqrt{2} \)

38% Answer Correctly
40\( \sqrt{50} \)
35\( \sqrt{2} \)
3\( \sqrt{2} \)
3\( \sqrt{25} \)

Solution

To subtract these radicals together their radicands must be the same:

8\( \sqrt{50} \) - 5\( \sqrt{2} \)
8\( \sqrt{25 \times 2} \) - 5\( \sqrt{2} \)
8\( \sqrt{5^2 \times 2} \) - 5\( \sqrt{2} \)
(8)(5)\( \sqrt{2} \) - 5\( \sqrt{2} \)
40\( \sqrt{2} \) - 5\( \sqrt{2} \)

Now that the radicands are identical, you can subtract them:

40\( \sqrt{2} \) - 5\( \sqrt{2} \)
(40 - 5)\( \sqrt{2} \)
35\( \sqrt{2} \)


3

Which of the following is a mixed number?

82% Answer Correctly

\(1 {2 \over 5} \)

\({5 \over 7} \)

\({7 \over 5} \)

\({a \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


4

Solve for \( \frac{3!}{6!} \)

67% Answer Correctly
336
120
\( \frac{1}{120} \)
15120

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{6!} \)
\( \frac{3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5 \times 4} \)
\( \frac{1}{120} \)


5

If the ratio of home fans to visiting fans in a crowd is 4:1 and all 49,000 seats in a stadium are filled, how many home fans are in attendance?

50% Answer Correctly
29,250
39,200
31,333
30,000

Solution

A ratio of 4:1 means that there are 4 home fans for every one visiting fan. So, of every 5 fans, 4 are home fans and \( \frac{4}{5} \) of every fan in the stadium is a home fan:

49,000 fans x \( \frac{4}{5} \) = \( \frac{196000}{5} \) = 39,200 fans.