| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.96 |
| Score | 0% | 59% |
What is \( \frac{4}{8} \) x \( \frac{4}{6} \)?
| 2 | |
| \(\frac{1}{3}\) | |
| \(\frac{1}{10}\) | |
| \(\frac{1}{14}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{8} \) x \( \frac{4}{6} \) = \( \frac{4 x 4}{8 x 6} \) = \( \frac{16}{48} \) = \(\frac{1}{3}\)
A tiger in a zoo has consumed 99 pounds of food in 9 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 165 pounds?
| 11 | |
| 6 | |
| 13 | |
| 10 |
If the tiger has consumed 99 pounds of food in 9 days that's \( \frac{99}{9} \) = 11 pounds of food per day. The tiger needs to consume 165 - 99 = 66 more pounds of food to reach 165 pounds total. At 11 pounds of food per day that's \( \frac{66}{11} \) = 6 more days.
16 members of a bridal party need transported to a wedding reception but there are only 3 5-passenger taxis available to take them. How many will need to find other transportation?
| 5 | |
| 7 | |
| 1 | |
| 6 |
There are 3 5-passenger taxis available so that's 3 x 5 = 15 total seats. There are 16 people needing transportation leaving 16 - 15 = 1 who will have to find other transportation.
What is \( 9 \)\( \sqrt{125} \) + \( 5 \)\( \sqrt{5} \)
| 50\( \sqrt{5} \) | |
| 45\( \sqrt{125} \) | |
| 14\( \sqrt{25} \) | |
| 45\( \sqrt{25} \) |
To add these radicals together their radicands must be the same:
9\( \sqrt{125} \) + 5\( \sqrt{5} \)
9\( \sqrt{25 \times 5} \) + 5\( \sqrt{5} \)
9\( \sqrt{5^2 \times 5} \) + 5\( \sqrt{5} \)
(9)(5)\( \sqrt{5} \) + 5\( \sqrt{5} \)
45\( \sqrt{5} \) + 5\( \sqrt{5} \)
Now that the radicands are identical, you can add them together:
45\( \sqrt{5} \) + 5\( \sqrt{5} \)\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for division |
|
commutative property for multiplication |
|
distributive property for multiplication |
|
distributive property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).