ASVAB Arithmetic Reasoning Practice Test 283240 Results

Your Results Global Average
Questions 5 5
Correct 0 2.96
Score 0% 59%

Review

1

What is \( \frac{4}{8} \) x \( \frac{4}{6} \)?

72% Answer Correctly
2
\(\frac{1}{3}\)
\(\frac{1}{10}\)
\(\frac{1}{14}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{8} \) x \( \frac{4}{6} \) = \( \frac{4 x 4}{8 x 6} \) = \( \frac{16}{48} \) = \(\frac{1}{3}\)


2

A tiger in a zoo has consumed 99 pounds of food in 9 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 165 pounds?

56% Answer Correctly
11
6
13
10

Solution

If the tiger has consumed 99 pounds of food in 9 days that's \( \frac{99}{9} \) = 11 pounds of food per day. The tiger needs to consume 165 - 99 = 66 more pounds of food to reach 165 pounds total. At 11 pounds of food per day that's \( \frac{66}{11} \) = 6 more days.


3

16 members of a bridal party need transported to a wedding reception but there are only 3 5-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
5
7
1
6

Solution

There are 3 5-passenger taxis available so that's 3 x 5 = 15 total seats. There are 16 people needing transportation leaving 16 - 15 = 1 who will have to find other transportation.


4

What is \( 9 \)\( \sqrt{125} \) + \( 5 \)\( \sqrt{5} \)

35% Answer Correctly
50\( \sqrt{5} \)
45\( \sqrt{125} \)
14\( \sqrt{25} \)
45\( \sqrt{25} \)

Solution

To add these radicals together their radicands must be the same:

9\( \sqrt{125} \) + 5\( \sqrt{5} \)
9\( \sqrt{25 \times 5} \) + 5\( \sqrt{5} \)
9\( \sqrt{5^2 \times 5} \) + 5\( \sqrt{5} \)
(9)(5)\( \sqrt{5} \) + 5\( \sqrt{5} \)
45\( \sqrt{5} \) + 5\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

45\( \sqrt{5} \) + 5\( \sqrt{5} \)
(45 + 5)\( \sqrt{5} \)
50\( \sqrt{5} \)


5

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

commutative property for division

commutative property for multiplication

distributive property for multiplication

distributive property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).