| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.10 |
| Score | 0% | 62% |
What is the distance in miles of a trip that takes 4 hours at an average speed of 45 miles per hour?
| 180 miles | |
| 135 miles | |
| 275 miles | |
| 200 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 45mph \times 4h \)
180 miles
Which of these numbers is a factor of 48?
| 12 | |
| 2 | |
| 24 | |
| 17 |
The factors of a number are all positive integers that divide evenly into the number. The factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.
Monica scored 80% on her final exam. If each question was worth 2 points and there were 120 possible points on the exam, how many questions did Monica answer correctly?
| 55 | |
| 34 | |
| 44 | |
| 48 |
Monica scored 80% on the test meaning she earned 80% of the possible points on the test. There were 120 possible points on the test so she earned 120 x 0.8 = 96 points. Each question is worth 2 points so she got \( \frac{96}{2} \) = 48 questions right.
What is 8\( \sqrt{9} \) x 9\( \sqrt{9} \)?
| 17\( \sqrt{81} \) | |
| 216\( \sqrt{9} \) | |
| 17\( \sqrt{9} \) | |
| 72\( \sqrt{9} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
8\( \sqrt{9} \) x 9\( \sqrt{9} \)
(8 x 9)\( \sqrt{9 \times 9} \)
72\( \sqrt{81} \)
Now we need to simplify the radical:
72\( \sqrt{81} \)
72\( \sqrt{9 \times 9} \)
72\( \sqrt{9 \times 3^2} \)
(72)(3)\( \sqrt{9} \)
216\( \sqrt{9} \)
The total water usage for a city is 20,000 gallons each day. Of that total, 29% is for personal use and 44% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 2,250 | |
| 3,000 | |
| 10,800 | |
| 5,200 |
44% of the water consumption is industrial use and 29% is personal use so (44% - 29%) = 15% more water is used for industrial purposes. 20,000 gallons are consumed daily so industry consumes \( \frac{15}{100} \) x 20,000 gallons = 3,000 gallons.