| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.07 |
| Score | 0% | 61% |
A bread recipe calls for 3\(\frac{3}{4}\) cups of flour. If you only have \(\frac{5}{8}\) cup, how much more flour is needed?
| 1\(\frac{3}{4}\) cups | |
| 3\(\frac{1}{8}\) cups | |
| 1\(\frac{7}{8}\) cups | |
| \(\frac{3}{4}\) cups |
The amount of flour you need is (3\(\frac{3}{4}\) - \(\frac{5}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{30}{8} \) - \( \frac{5}{8} \)) cups
\( \frac{25}{8} \) cups
3\(\frac{1}{8}\) cups
22 members of a bridal party need transported to a wedding reception but there are only 4 5-passenger taxis available to take them. How many will need to find other transportation?
| 3 | |
| 2 | |
| 8 | |
| 4 |
There are 4 5-passenger taxis available so that's 4 x 5 = 20 total seats. There are 22 people needing transportation leaving 22 - 20 = 2 who will have to find other transportation.
What is 2\( \sqrt{9} \) x 7\( \sqrt{9} \)?
| 9\( \sqrt{81} \) | |
| 14\( \sqrt{18} \) | |
| 42\( \sqrt{9} \) | |
| 9\( \sqrt{9} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
2\( \sqrt{9} \) x 7\( \sqrt{9} \)
(2 x 7)\( \sqrt{9 \times 9} \)
14\( \sqrt{81} \)
Now we need to simplify the radical:
14\( \sqrt{81} \)
14\( \sqrt{9 \times 9} \)
14\( \sqrt{9 \times 3^2} \)
(14)(3)\( \sqrt{9} \)
42\( \sqrt{9} \)
4! = ?
4 x 3 x 2 x 1 |
|
3 x 2 x 1 |
|
5 x 4 x 3 x 2 x 1 |
|
4 x 3 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
On average, the center for a basketball team hits 30% of his shots while a guard on the same team hits 35% of his shots. If the guard takes 20 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 30 | |
| 23 | |
| 26 | |
| 32 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 20 x \( \frac{35}{100} \) = \( \frac{35 x 20}{100} \) = \( \frac{700}{100} \) = 7 shots
The center makes 30% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{7}{\frac{30}{100}} \) = 7 x \( \frac{100}{30} \) = \( \frac{7 x 100}{30} \) = \( \frac{700}{30} \) = 23 shots
to make the same number of shots as the guard and thus score the same number of points.