| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.98 |
| Score | 0% | 60% |
In a class of 27 students, 12 are taking German and 8 are taking Spanish. Of the students studying German or Spanish, 4 are taking both courses. How many students are not enrolled in either course?
| 11 | |
| 13 | |
| 18 | |
| 23 |
The number of students taking German or Spanish is 12 + 8 = 20. Of that group of 20, 4 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 20 - 4 = 16 who are taking at least one language. 27 - 16 = 11 students who are not taking either language.
A triathlon course includes a 100m swim, a 50.7km bike ride, and a 15.3km run. What is the total length of the race course?
| 66.1km | |
| 51.1km | |
| 44.2km | |
| 22.6km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.1km + 50.7km + 15.3km
total distance = 66.1km
What is \( \frac{-5b^7}{7b^4} \)?
| -\(\frac{5}{7}\)b3 | |
| -\(\frac{5}{7}\)b-3 | |
| -\(\frac{5}{7}\)b28 | |
| -1\(\frac{2}{5}\)b3 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-5b^7}{7b^4} \)
\( \frac{-5}{7} \) b(7 - 4)
-\(\frac{5}{7}\)b3
What is 8c2 - 4c2?
| 4c2 | |
| 4c-2 | |
| -4c2 | |
| 12c4 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
8c2 - 4c2
(8 - 4)c2
4c2
What is \( 2 \)\( \sqrt{80} \) + \( 8 \)\( \sqrt{5} \)
| 16\( \sqrt{80} \) | |
| 16\( \sqrt{5} \) | |
| 16\( \sqrt{400} \) | |
| 10\( \sqrt{5} \) |
To add these radicals together their radicands must be the same:
2\( \sqrt{80} \) + 8\( \sqrt{5} \)
2\( \sqrt{16 \times 5} \) + 8\( \sqrt{5} \)
2\( \sqrt{4^2 \times 5} \) + 8\( \sqrt{5} \)
(2)(4)\( \sqrt{5} \) + 8\( \sqrt{5} \)
8\( \sqrt{5} \) + 8\( \sqrt{5} \)
Now that the radicands are identical, you can add them together:
8\( \sqrt{5} \) + 8\( \sqrt{5} \)