ASVAB Arithmetic Reasoning Practice Test 287111 Results

Your Results Global Average
Questions 5 5
Correct 0 3.13
Score 0% 63%

Review

1

What is \( \frac{9}{5} \) + \( \frac{7}{9} \)?

60% Answer Correctly
1 \( \frac{4}{11} \)
\( \frac{6}{45} \)
2\(\frac{26}{45}\)
\( \frac{3}{45} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 5 and 9 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{9 x 9}{5 x 9} \) + \( \frac{7 x 5}{9 x 5} \)

\( \frac{81}{45} \) + \( \frac{35}{45} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{81 + 35}{45} \) = \( \frac{116}{45} \) = 2\(\frac{26}{45}\)


2

What is \( \frac{5b^6}{3b^3} \)?

60% Answer Correctly
\(\frac{3}{5}\)b3
1\(\frac{2}{3}\)b9
1\(\frac{2}{3}\)b3
1\(\frac{2}{3}\)b\(\frac{1}{2}\)

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{5b^6}{3b^3} \)
\( \frac{5}{3} \) b(6 - 3)
1\(\frac{2}{3}\)b3


3

What is \( \frac{3}{6} \) x \( \frac{3}{6} \)?

72% Answer Correctly
\(\frac{1}{4}\)
\(\frac{1}{7}\)
\(\frac{12}{49}\)
\(\frac{4}{63}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{6} \) x \( \frac{3}{6} \) = \( \frac{3 x 3}{6 x 6} \) = \( \frac{9}{36} \) = \(\frac{1}{4}\)


4

53% Answer Correctly
1
1.4
5.6
1.6

Solution


1


5

If \(\left|a\right| = 7\), which of the following best describes a?

67% Answer Correctly

a = 7

a = 7 or a = -7

a = -7

none of these is correct


Solution

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).