| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.34 |
| Score | 0% | 67% |
What is the greatest common factor of 52 and 72?
| 4 | |
| 45 | |
| 29 | |
| 1 |
The factors of 52 are [1, 2, 4, 13, 26, 52] and the factors of 72 are [1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72]. They share 3 factors [1, 2, 4] making 4 the greatest factor 52 and 72 have in common.
Monty loaned Frank $500 at an annual interest rate of 4%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $20 | |
| $4 | |
| $5 | |
| $8 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $500
i = 0.04 x $500
i = $20
On average, the center for a basketball team hits 45% of his shots while a guard on the same team hits 55% of his shots. If the guard takes 25 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 32 | |
| 29 | |
| 43 | |
| 25 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 25 x \( \frac{55}{100} \) = \( \frac{55 x 25}{100} \) = \( \frac{1375}{100} \) = 13 shots
The center makes 45% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{13}{\frac{45}{100}} \) = 13 x \( \frac{100}{45} \) = \( \frac{13 x 100}{45} \) = \( \frac{1300}{45} \) = 29 shots
to make the same number of shots as the guard and thus score the same number of points.
Find the average of the following numbers: 13, 9, 15, 7.
| 16 | |
| 15 | |
| 13 | |
| 11 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{13 + 9 + 15 + 7}{4} \) = \( \frac{44}{4} \) = 11
In a class of 23 students, 5 are taking German and 14 are taking Spanish. Of the students studying German or Spanish, 3 are taking both courses. How many students are not enrolled in either course?
| 20 | |
| 7 | |
| 23 | |
| 21 |
The number of students taking German or Spanish is 5 + 14 = 19. Of that group of 19, 3 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 19 - 3 = 16 who are taking at least one language. 23 - 16 = 7 students who are not taking either language.