ASVAB Arithmetic Reasoning Practice Test 288768 Results

Your Results Global Average
Questions 5 5
Correct 0 2.97
Score 0% 59%

Review

1

How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 10 gallon tank to fill it exactly halfway?

52% Answer Correctly
6
5
4
2

Solution

To fill a 10 gallon tank exactly halfway you'll need 5 gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:

cans = \( \frac{5 \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 2


2

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

55% Answer Correctly

distributive property for multiplication

commutative property for division

commutative property for multiplication

distributive property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


3

What is \( \frac{16\sqrt{27}}{8\sqrt{9}} \)?

71% Answer Correctly
\(\frac{1}{3}\) \( \sqrt{2} \)
3 \( \sqrt{2} \)
2 \( \sqrt{\frac{1}{3}} \)
2 \( \sqrt{3} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{16\sqrt{27}}{8\sqrt{9}} \)
\( \frac{16}{8} \) \( \sqrt{\frac{27}{9}} \)
2 \( \sqrt{3} \)


4

What is (x5)5?

79% Answer Correctly
5x5
x0
x10
x25

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(x5)5
x(5 * 5)
x25


5

What is 9\( \sqrt{4} \) x 6\( \sqrt{8} \)?

41% Answer Correctly
15\( \sqrt{8} \)
15\( \sqrt{32} \)
54\( \sqrt{4} \)
216\( \sqrt{2} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

9\( \sqrt{4} \) x 6\( \sqrt{8} \)
(9 x 6)\( \sqrt{4 \times 8} \)
54\( \sqrt{32} \)

Now we need to simplify the radical:

54\( \sqrt{32} \)
54\( \sqrt{2 \times 16} \)
54\( \sqrt{2 \times 4^2} \)
(54)(4)\( \sqrt{2} \)
216\( \sqrt{2} \)