ASVAB Arithmetic Reasoning Practice Test 292855 Results

Your Results Global Average
Questions 5 5
Correct 0 2.95
Score 0% 59%

Review

1

Which of the following is not an integer?

77% Answer Correctly

0

\({1 \over 2}\)

-1

1


Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.


2

If there were a total of 200 raffle tickets sold and you bought 4 tickets, what's the probability that you'll win the raffle?

60% Answer Correctly
11%
1%
2%
9%

Solution

You have 4 out of the total of 200 raffle tickets sold so you have a (\( \frac{4}{200} \)) x 100 = \( \frac{4 \times 100}{200} \) = \( \frac{400}{200} \) = 2% chance to win the raffle.


3

Christine scored 80% on her final exam. If each question was worth 4 points and there were 360 possible points on the exam, how many questions did Christine answer correctly?

57% Answer Correctly
69
59
79
72

Solution

Christine scored 80% on the test meaning she earned 80% of the possible points on the test. There were 360 possible points on the test so she earned 360 x 0.8 = 288 points. Each question is worth 4 points so she got \( \frac{288}{4} \) = 72 questions right.


4

If \( \left|z + 4\right| \) - 3 = 3, which of these is a possible value for z?

62% Answer Correctly
-8
2
0
4

Solution

First, solve for \( \left|z + 4\right| \):

\( \left|z + 4\right| \) - 3 = 3
\( \left|z + 4\right| \) = 3 + 3
\( \left|z + 4\right| \) = 6

The value inside the absolute value brackets can be either positive or negative so (z + 4) must equal + 6 or -6 for \( \left|z + 4\right| \) to equal 6:

z + 4 = 6
z = 6 - 4
z = 2
z + 4 = -6
z = -6 - 4
z = -10

So, z = -10 or z = 2.


5

What is \( 8 \)\( \sqrt{20} \) + \( 6 \)\( \sqrt{5} \)

35% Answer Correctly
14\( \sqrt{5} \)
14\( \sqrt{20} \)
48\( \sqrt{5} \)
22\( \sqrt{5} \)

Solution

To add these radicals together their radicands must be the same:

8\( \sqrt{20} \) + 6\( \sqrt{5} \)
8\( \sqrt{4 \times 5} \) + 6\( \sqrt{5} \)
8\( \sqrt{2^2 \times 5} \) + 6\( \sqrt{5} \)
(8)(2)\( \sqrt{5} \) + 6\( \sqrt{5} \)
16\( \sqrt{5} \) + 6\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

16\( \sqrt{5} \) + 6\( \sqrt{5} \)
(16 + 6)\( \sqrt{5} \)
22\( \sqrt{5} \)