| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.60 |
| Score | 0% | 52% |
What is 9y6 + 7y6?
| 16y6 | |
| 16y36 | |
| 16y-12 | |
| 2y-6 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
9y6 + 7y6
(9 + 7)y6
16y6
On average, the center for a basketball team hits 35% of his shots while a guard on the same team hits 50% of his shots. If the guard takes 15 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 33 | |
| 23 | |
| 20 | |
| 13 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{50}{100} \) = \( \frac{50 x 15}{100} \) = \( \frac{750}{100} \) = 7 shots
The center makes 35% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{7}{\frac{35}{100}} \) = 7 x \( \frac{100}{35} \) = \( \frac{7 x 100}{35} \) = \( \frac{700}{35} \) = 20 shots
to make the same number of shots as the guard and thus score the same number of points.
What is \( 8 \)\( \sqrt{8} \) + \( 7 \)\( \sqrt{2} \)
| 15\( \sqrt{4} \) | |
| 23\( \sqrt{2} \) | |
| 56\( \sqrt{4} \) | |
| 15\( \sqrt{16} \) |
To add these radicals together their radicands must be the same:
8\( \sqrt{8} \) + 7\( \sqrt{2} \)
8\( \sqrt{4 \times 2} \) + 7\( \sqrt{2} \)
8\( \sqrt{2^2 \times 2} \) + 7\( \sqrt{2} \)
(8)(2)\( \sqrt{2} \) + 7\( \sqrt{2} \)
16\( \sqrt{2} \) + 7\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
16\( \sqrt{2} \) + 7\( \sqrt{2} \)What is 6\( \sqrt{4} \) x 4\( \sqrt{9} \)?
| 10\( \sqrt{9} \) | |
| 24\( \sqrt{9} \) | |
| 144 | |
| 10\( \sqrt{4} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
6\( \sqrt{4} \) x 4\( \sqrt{9} \)
(6 x 4)\( \sqrt{4 \times 9} \)
24\( \sqrt{36} \)
Now we need to simplify the radical:
24\( \sqrt{36} \)
24\( \sqrt{6^2} \)
(24)(6)
144
What is \( \frac{3}{6} \) x \( \frac{2}{8} \)?
| \(\frac{1}{8}\) | |
| \(\frac{1}{14}\) | |
| \(\frac{3}{56}\) | |
| \(\frac{3}{4}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{6} \) x \( \frac{2}{8} \) = \( \frac{3 x 2}{6 x 8} \) = \( \frac{6}{48} \) = \(\frac{1}{8}\)