If 32% of the town's 33,000 voters cast ballots the number of votes cast is:

(\( \frac{32}{100} \)) x 33,000 = \( \frac{1,056,000}{100} \) = 10,560

The mayor got 74% of the votes cast which is:

(\( \frac{74}{100} \)) x 10,560 = \( \frac{781,440}{100} \) = 7,814 votes.

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 4 and 6 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{2 x 3}{4 x 3} \) + \( \frac{4 x 2}{6 x 2} \)

\( \frac{6}{12} \) + \( \frac{8}{12} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{6 + 8}{12} \) = \( \frac{14}{12} \) = 1\(\frac{1}{6}\)

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 20 workers at the company now and that's enough to staff 5 crews so there are \( \frac{20}{5} \) = 4 workers on a crew. 8 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 8 x 4 = 32 total workers to staff the crews during the busy season. The company already employs 20 workers so they need to add 32 - 20 = 12 new staff for the busy season.

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.

If the tiger has consumed 64 pounds of food in 8 days that's \( \frac{64}{8} \) = 8 pounds of food per day. The tiger needs to consume 120 - 64 = 56 more pounds of food to reach 120 pounds total. At 8 pounds of food per day that's \( \frac{56}{8} \) = 7 more days.