| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.09 |
| Score | 0% | 62% |
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for multiplication |
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commutative property for multiplication |
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commutative property for division |
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distributive property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
If there were a total of 400 raffle tickets sold and you bought 32 tickets, what's the probability that you'll win the raffle?
| 8% | |
| 3% | |
| 7% | |
| 6% |
You have 32 out of the total of 400 raffle tickets sold so you have a (\( \frac{32}{400} \)) x 100 = \( \frac{32 \times 100}{400} \) = \( \frac{3200}{400} \) = 8% chance to win the raffle.
If the ratio of home fans to visiting fans in a crowd is 5:1 and all 48,000 seats in a stadium are filled, how many home fans are in attendance?
| 33,333 | |
| 27,000 | |
| 20,000 | |
| 40,000 |
A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:
48,000 fans x \( \frac{5}{6} \) = \( \frac{240000}{6} \) = 40,000 fans.
5 members of a bridal party need transported to a wedding reception but there are only 2 2-passenger taxis available to take them. How many will need to find other transportation?
| 1 | |
| 5 | |
| 6 | |
| 7 |
There are 2 2-passenger taxis available so that's 2 x 2 = 4 total seats. There are 5 people needing transportation leaving 5 - 4 = 1 who will have to find other transportation.
Convert y-2 to remove the negative exponent.
| \( \frac{-1}{y^{-2}} \) | |
| \( \frac{-1}{-2y} \) | |
| \( \frac{1}{y^2} \) | |
| \( \frac{-2}{-y} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.