| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.24 |
| Score | 0% | 65% |
Simplify \( \frac{28}{44} \).
| \( \frac{5}{18} \) | |
| \( \frac{7}{11} \) | |
| \( \frac{10}{11} \) | |
| \( \frac{5}{7} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 28 are [1, 2, 4, 7, 14, 28] and the factors of 44 are [1, 2, 4, 11, 22, 44]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{28}{44} \) = \( \frac{\frac{28}{4}}{\frac{44}{4}} \) = \( \frac{7}{11} \)
The total water usage for a city is 45,000 gallons each day. Of that total, 10% is for personal use and 20% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 2,000 | |
| 9,500 | |
| 6,300 | |
| 4,500 |
20% of the water consumption is industrial use and 10% is personal use so (20% - 10%) = 10% more water is used for industrial purposes. 45,000 gallons are consumed daily so industry consumes \( \frac{10}{100} \) x 45,000 gallons = 4,500 gallons.
Which of the following is an improper fraction?
\({2 \over 5} \) |
|
\({a \over 5} \) |
|
\({7 \over 5} \) |
|
\(1 {2 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
How many 1\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 15 gallon tank to fill it exactly halfway?
| 3 | |
| 10 | |
| 4 | |
| 5 |
To fill a 15 gallon tank exactly halfway you'll need 7\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:
cans = \( \frac{7\frac{1}{2} \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 5
What is 2z5 + 9z5?
| 7z-5 | |
| 11z5 | |
| -7z-5 | |
| 7z5 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
2z5 + 9z5
(2 + 9)z5
11z5