Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (5 + 5) ÷ 3 x 5 - 4²
P: 2 + (10) ÷ 3 x 5 - 4²
E: 2 + 10 ÷ 3 x 5 - 16
MD: 2 + \( \frac{10}{3} \) x 5 - 16
MD: 2 + \( \frac{50}{3} \) - 16
AS: \( \frac{6}{3} \) + \( \frac{50}{3} \) - 16
AS: \( \frac{56}{3} \) - 16
AS: \( \frac{56 - 48}{3} \)
\( \frac{8}{3} \)
2\(\frac{2}{3}\)

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 24 meters so the equation becomes: 2w + 2h = 24.

Putting these two equations together and solving for width (w):

2w + 2h = 24
w + h = \( \frac{24}{2} \)
w + h = 12
w = 12 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 12 - 2w
3w = 12
w = \( \frac{12}{3} \)
w = 4

Since h = 2w that makes h = (2 x 4) = 8 and the area = h x w = 4 x 8 = 32 m²

The greatest common factor (GCF) is the greatest factor that divides two integers.

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{9} \) x \( \frac{1}{8} \) = \( \frac{4 x 1}{9 x 8} \) = \( \frac{4}{72} \) = \(\frac{1}{18}\)