ASVAB Arithmetic Reasoning Practice Test 30195 Results

Your Results Global Average
Questions 5 5
Correct 0 3.09
Score 0% 62%

Review

1

A machine in a factory has an error rate of 6 parts per 100. The machine normally runs 24 hours a day and produces 7 parts per hour. Yesterday the machine was shut down for 4 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
78.4
147.2
131.6
116.4

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{6}{100} \) x 7 = \( \frac{6 \times 7}{100} \) = \( \frac{42}{100} \) = 0.42 errors per hour

So, in an average hour, the machine will produce 7 - 0.42 = 6.58 error free parts.

The machine ran for 24 - 4 = 20 hours yesterday so you would expect that 20 x 6.58 = 131.6 error free parts were produced yesterday.


2

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 35% off." If Ezra buys two shirts, each with a regular price of $42, how much will he pay for both shirts?

57% Answer Correctly
$14.70
$27.30
$69.30
$50.40

Solution

By buying two shirts, Ezra will save $42 x \( \frac{35}{100} \) = \( \frac{$42 x 35}{100} \) = \( \frac{$1470}{100} \) = $14.70 on the second shirt.

So, his total cost will be
$42.00 + ($42.00 - $14.70)
$42.00 + $27.30
$69.30


3

Solve for \( \frac{4!}{3!} \)

67% Answer Correctly
\( \frac{1}{5} \)
\( \frac{1}{56} \)
42
4

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{4!}{3!} \)
\( \frac{4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} \)
\( \frac{4}{1} \)
4


4

If \( \left|z + 5\right| \) - 1 = 2, which of these is a possible value for z?

62% Answer Correctly
-25
-6
-8
12

Solution

First, solve for \( \left|z + 5\right| \):

\( \left|z + 5\right| \) - 1 = 2
\( \left|z + 5\right| \) = 2 + 1
\( \left|z + 5\right| \) = 3

The value inside the absolute value brackets can be either positive or negative so (z + 5) must equal + 3 or -3 for \( \left|z + 5\right| \) to equal 3:

z + 5 = 3
z = 3 - 5
z = -2
z + 5 = -3
z = -3 - 5
z = -8

So, z = -8 or z = -2.


5

Find the average of the following numbers: 16, 14, 19, 11.

74% Answer Correctly
17
15
12
10

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{16 + 14 + 19 + 11}{4} \) = \( \frac{60}{4} \) = 15