| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.09 |
| Score | 0% | 62% |
A machine in a factory has an error rate of 6 parts per 100. The machine normally runs 24 hours a day and produces 7 parts per hour. Yesterday the machine was shut down for 4 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 78.4 | |
| 147.2 | |
| 131.6 | |
| 116.4 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{6}{100} \) x 7 = \( \frac{6 \times 7}{100} \) = \( \frac{42}{100} \) = 0.42 errors per hour
So, in an average hour, the machine will produce 7 - 0.42 = 6.58 error free parts.
The machine ran for 24 - 4 = 20 hours yesterday so you would expect that 20 x 6.58 = 131.6 error free parts were produced yesterday.
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 35% off." If Ezra buys two shirts, each with a regular price of $42, how much will he pay for both shirts?
| $14.70 | |
| $27.30 | |
| $69.30 | |
| $50.40 |
By buying two shirts, Ezra will save $42 x \( \frac{35}{100} \) = \( \frac{$42 x 35}{100} \) = \( \frac{$1470}{100} \) = $14.70 on the second shirt.
So, his total cost will be
$42.00 + ($42.00 - $14.70)
$42.00 + $27.30
$69.30
Solve for \( \frac{4!}{3!} \)
| \( \frac{1}{5} \) | |
| \( \frac{1}{56} \) | |
| 42 | |
| 4 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{4!}{3!} \)
\( \frac{4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} \)
\( \frac{4}{1} \)
4
If \( \left|z + 5\right| \) - 1 = 2, which of these is a possible value for z?
| -25 | |
| -6 | |
| -8 | |
| 12 |
First, solve for \( \left|z + 5\right| \):
\( \left|z + 5\right| \) - 1 = 2
\( \left|z + 5\right| \) = 2 + 1
\( \left|z + 5\right| \) = 3
The value inside the absolute value brackets can be either positive or negative so (z + 5) must equal + 3 or -3 for \( \left|z + 5\right| \) to equal 3:
| z + 5 = 3 z = 3 - 5 z = -2 | z + 5 = -3 z = -3 - 5 z = -8 |
So, z = -8 or z = -2.
Find the average of the following numbers: 16, 14, 19, 11.
| 17 | |
| 15 | |
| 12 | |
| 10 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{16 + 14 + 19 + 11}{4} \) = \( \frac{60}{4} \) = 15