| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.68 |
| Score | 0% | 74% |
17 members of a bridal party need transported to a wedding reception but there are only 3 4-passenger taxis available to take them. How many will need to find other transportation?
| 5 | |
| 8 | |
| 1 | |
| 9 |
There are 3 4-passenger taxis available so that's 3 x 4 = 12 total seats. There are 17 people needing transportation leaving 17 - 12 = 5 who will have to find other transportation.
How many hours does it take a car to travel 140 miles at an average speed of 35 miles per hour?
| 6 hours | |
| 1 hour | |
| 9 hours | |
| 4 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{140mi}{35mph} \)
4 hours
What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?
| 29 | |
| 34 | |
| 32 | |
| 31 |
The equation for this sequence is:
an = an-1 + 2(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31
What is \( \frac{63\sqrt{4}}{9\sqrt{2}} \)?
| \(\frac{1}{2}\) \( \sqrt{\frac{1}{7}} \) | |
| 2 \( \sqrt{7} \) | |
| 7 \( \sqrt{\frac{1}{2}} \) | |
| 7 \( \sqrt{2} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{63\sqrt{4}}{9\sqrt{2}} \)
\( \frac{63}{9} \) \( \sqrt{\frac{4}{2}} \)
7 \( \sqrt{2} \)
Solve for \( \frac{4!}{2!} \)
| \( \frac{1}{6} \) | |
| 42 | |
| \( \frac{1}{7} \) | |
| 12 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{4!}{2!} \)
\( \frac{4 \times 3 \times 2 \times 1}{2 \times 1} \)
\( \frac{4 \times 3}{1} \)
\( 4 \times 3 \)
12