ASVAB Arithmetic Reasoning Practice Test 306023 Results

Your Results Global Average
Questions 5 5
Correct 0 3.36
Score 0% 67%

Review

1

If a rectangle is twice as long as it is wide and has a perimeter of 48 meters, what is the area of the rectangle?

47% Answer Correctly
32 m2
162 m2
8 m2
128 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 48 meters so the equation becomes: 2w + 2h = 48.

Putting these two equations together and solving for width (w):

2w + 2h = 48
w + h = \( \frac{48}{2} \)
w + h = 24
w = 24 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 24 - 2w
3w = 24
w = \( \frac{24}{3} \)
w = 8

Since h = 2w that makes h = (2 x 8) = 16 and the area = h x w = 8 x 16 = 128 m2


2

What is (y3)3?

80% Answer Correctly
3y3
y6
y9
y0

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(y3)3
y(3 * 3)
y9


3

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

improper fraction

fraction

mixed number

integer


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


4

Convert z-3 to remove the negative exponent.

68% Answer Correctly
\( \frac{1}{z^3} \)
\( \frac{1}{z^{-3}} \)
\( \frac{-1}{z^{-3}} \)
\( \frac{-1}{-3z^{3}} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


5

If \( \left|a - 2\right| \) - 9 = 1, which of these is a possible value for a?

62% Answer Correctly
6
2
13
12

Solution

First, solve for \( \left|a - 2\right| \):

\( \left|a - 2\right| \) - 9 = 1
\( \left|a - 2\right| \) = 1 + 9
\( \left|a - 2\right| \) = 10

The value inside the absolute value brackets can be either positive or negative so (a - 2) must equal + 10 or -10 for \( \left|a - 2\right| \) to equal 10:

a - 2 = 10
a = 10 + 2
a = 12
a - 2 = -10
a = -10 + 2
a = -8

So, a = -8 or a = 12.