To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

1y⁶ + 2y⁶
(1 + 2)y⁶
3y⁶

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.

If a single cook can bake 4 large cakes per hour and the kitchen is available for 2 hours, a single cook can bake 4 x 2 = 8 large cakes during that time. 39 large cakes are needed for the party so \( \frac{39}{8} \) = 4\(\frac{7}{8}\) cooks are needed to bake the required number of large cakes.

If a single cook can bake 12 small cakes per hour and the kitchen is available for 2 hours, a single cook can bake 12 x 2 = 24 small cakes during that time. 270 small cakes are needed for the party so \( \frac{270}{24} \) = 11\(\frac{1}{4}\) cooks are needed to bake the required number of small cakes.

Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 5 + 12 = 17 cooks.

The greatest common factor (GCF) is the greatest factor that divides two integers.

First, solve for \( \left|c - 9\right| \):

\( \left|c - 9\right| \) - 2 = 7
\( \left|c - 9\right| \) = 7 + 2
\( \left|c - 9\right| \) = 9

The value inside the absolute value brackets can be either positive or negative so (c - 9) must equal + 9 or -9 for \( \left|c - 9\right| \) to equal 9:

So, c = 0 or c = 18.