| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.14 |
| Score | 0% | 63% |
The __________ is the greatest factor that divides two integers.
least common multiple |
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absolute value |
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greatest common factor |
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greatest common multiple |
The greatest common factor (GCF) is the greatest factor that divides two integers.
How many 16-passenger vans will it take to drive all 85 members of the football team to an away game?
| 9 vans | |
| 4 vans | |
| 10 vans | |
| 6 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{85}{16} \) = 5\(\frac{5}{16}\)
So, it will take 5 full vans and one partially full van to transport the entire team making a total of 6 vans.
Solve for \( \frac{5!}{2!} \)
| 210 | |
| 3024 | |
| \( \frac{1}{72} \) | |
| 60 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{5!}{2!} \)
\( \frac{5 \times 4 \times 3 \times 2 \times 1}{2 \times 1} \)
\( \frac{5 \times 4 \times 3}{1} \)
\( 5 \times 4 \times 3 \)
60
If a rectangle is twice as long as it is wide and has a perimeter of 18 meters, what is the area of the rectangle?
| 50 m2 | |
| 128 m2 | |
| 8 m2 | |
| 18 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 18 meters so the equation becomes: 2w + 2h = 18.
Putting these two equations together and solving for width (w):
2w + 2h = 18
w + h = \( \frac{18}{2} \)
w + h = 9
w = 9 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 9 - 2w
3w = 9
w = \( \frac{9}{3} \)
w = 3
Since h = 2w that makes h = (2 x 3) = 6 and the area = h x w = 3 x 6 = 18 m2
How many 1 gallon cans worth of fuel would you need to pour into an empty 4 gallon tank to fill it exactly halfway?
| 5 | |
| 4 | |
| 7 | |
| 2 |
To fill a 4 gallon tank exactly halfway you'll need 2 gallons of fuel. Each fuel can holds 1 gallons so:
cans = \( \frac{2 \text{ gallons}}{1 \text{ gallons}} \) = 2