| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.16 |
| Score | 0% | 63% |
Solve 4 + (3 + 2) ÷ 2 x 3 - 42
| 2 | |
| 3\(\frac{1}{2}\) | |
| \(\frac{3}{8}\) | |
| -4\(\frac{1}{2}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
4 + (3 + 2) ÷ 2 x 3 - 42
P: 4 + (5) ÷ 2 x 3 - 42
E: 4 + 5 ÷ 2 x 3 - 16
MD: 4 + \( \frac{5}{2} \) x 3 - 16
MD: 4 + \( \frac{15}{2} \) - 16
AS: \( \frac{8}{2} \) + \( \frac{15}{2} \) - 16
AS: \( \frac{23}{2} \) - 16
AS: \( \frac{23 - 32}{2} \)
\( \frac{-9}{2} \)
-4\(\frac{1}{2}\)
4! = ?
4 x 3 |
|
4 x 3 x 2 x 1 |
|
3 x 2 x 1 |
|
5 x 4 x 3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
What is 6a4 + 4a4?
| 10a4 | |
| 2a4 | |
| -2a-4 | |
| 10a8 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
6a4 + 4a4
(6 + 4)a4
10a4
On average, the center for a basketball team hits 40% of his shots while a guard on the same team hits 45% of his shots. If the guard takes 25 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 24 | |
| 28 | |
| 33 | |
| 20 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 25 x \( \frac{45}{100} \) = \( \frac{45 x 25}{100} \) = \( \frac{1125}{100} \) = 11 shots
The center makes 40% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{11}{\frac{40}{100}} \) = 11 x \( \frac{100}{40} \) = \( \frac{11 x 100}{40} \) = \( \frac{1100}{40} \) = 28 shots
to make the same number of shots as the guard and thus score the same number of points.
A triathlon course includes a 500m swim, a 20.1km bike ride, and a 12.100000000000001km run. What is the total length of the race course?
| 61.8km | |
| 35.2km | |
| 32.7km | |
| 31.4km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 500 meters to kilometers, divide the distance by 1000 to get 0.5km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.5km + 20.1km + 12.100000000000001km
total distance = 32.7km