| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.15 |
| Score | 0% | 63% |
A bread recipe calls for 1\(\frac{7}{8}\) cups of flour. If you only have \(\frac{3}{4}\) cup, how much more flour is needed?
| 1\(\frac{7}{8}\) cups | |
| 2\(\frac{3}{4}\) cups | |
| 3 cups | |
| 1\(\frac{1}{8}\) cups |
The amount of flour you need is (1\(\frac{7}{8}\) - \(\frac{3}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{15}{8} \) - \( \frac{6}{8} \)) cups
\( \frac{9}{8} \) cups
1\(\frac{1}{8}\) cups
If a mayor is elected with 72% of the votes cast and 53% of a town's 46,000 voters cast a vote, how many votes did the mayor receive?
| 20,723 | |
| 19,748 | |
| 17,554 | |
| 18,773 |
If 53% of the town's 46,000 voters cast ballots the number of votes cast is:
(\( \frac{53}{100} \)) x 46,000 = \( \frac{2,438,000}{100} \) = 24,380
The mayor got 72% of the votes cast which is:
(\( \frac{72}{100} \)) x 24,380 = \( \frac{1,755,360}{100} \) = 17,554 votes.
If \( \left|z + 5\right| \) - 8 = 2, which of these is a possible value for z?
| -4 | |
| 1 | |
| 5 | |
| 4 |
First, solve for \( \left|z + 5\right| \):
\( \left|z + 5\right| \) - 8 = 2
\( \left|z + 5\right| \) = 2 + 8
\( \left|z + 5\right| \) = 10
The value inside the absolute value brackets can be either positive or negative so (z + 5) must equal + 10 or -10 for \( \left|z + 5\right| \) to equal 10:
| z + 5 = 10 z = 10 - 5 z = 5 | z + 5 = -10 z = -10 - 5 z = -15 |
So, z = -15 or z = 5.
What is \( \frac{-2y^6}{9y^3} \)?
| -\(\frac{2}{9}\)y3 | |
| -\(\frac{2}{9}\)y-3 | |
| -\(\frac{2}{9}\)y9 | |
| -\(\frac{2}{9}\)y2 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-2y^6}{9y^3} \)
\( \frac{-2}{9} \) y(6 - 3)
-\(\frac{2}{9}\)y3
How many 8-passenger vans will it take to drive all 71 members of the football team to an away game?
| 5 vans | |
| 8 vans | |
| 6 vans | |
| 9 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{71}{8} \) = 8\(\frac{7}{8}\)
So, it will take 8 full vans and one partially full van to transport the entire team making a total of 9 vans.