| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.35 |
| Score | 0% | 67% |
The __________ is the greatest factor that divides two integers.
greatest common multiple |
|
absolute value |
|
least common multiple |
|
greatest common factor |
The greatest common factor (GCF) is the greatest factor that divides two integers.
A circular logo is enlarged to fit the lid of a jar. The new diameter is 35% larger than the original. By what percentage has the area of the logo increased?
| 35% | |
| 17\(\frac{1}{2}\)% | |
| 27\(\frac{1}{2}\)% | |
| 20% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 35% the radius (and, consequently, the total area) increases by \( \frac{35\text{%}}{2} \) = 17\(\frac{1}{2}\)%
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 5% off." If Ezra buys two shirts, each with a regular price of $26, how much money will he save?
| $5.20 | |
| $6.50 | |
| $7.80 | |
| $1.30 |
By buying two shirts, Ezra will save $26 x \( \frac{5}{100} \) = \( \frac{$26 x 5}{100} \) = \( \frac{$130}{100} \) = $1.30 on the second shirt.
A bread recipe calls for 3\(\frac{3}{8}\) cups of flour. If you only have \(\frac{1}{2}\) cup, how much more flour is needed?
| 1\(\frac{1}{4}\) cups | |
| 1\(\frac{3}{8}\) cups | |
| 2 cups | |
| 2\(\frac{7}{8}\) cups |
The amount of flour you need is (3\(\frac{3}{8}\) - \(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{27}{8} \) - \( \frac{4}{8} \)) cups
\( \frac{23}{8} \) cups
2\(\frac{7}{8}\) cups
How many hours does it take a car to travel 495 miles at an average speed of 55 miles per hour?
| 7 hours | |
| 9 hours | |
| 8 hours | |
| 6 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{495mi}{55mph} \)
9 hours