| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.16 |
| Score | 0% | 63% |
What is \( \frac{3}{2} \) + \( \frac{8}{10} \)?
| 1 \( \frac{5}{10} \) | |
| \( \frac{7}{10} \) | |
| \( \frac{6}{10} \) | |
| 2\(\frac{3}{10}\) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [10, 20, 30, 40, 50] making 10 the smallest multiple 2 and 10 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{3 x 5}{2 x 5} \) + \( \frac{8 x 1}{10 x 1} \)
\( \frac{15}{10} \) + \( \frac{8}{10} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{15 + 8}{10} \) = \( \frac{23}{10} \) = 2\(\frac{3}{10}\)
Betty scored 92% on her final exam. If each question was worth 3 points and there were 300 possible points on the exam, how many questions did Betty answer correctly?
| 92 | |
| 105 | |
| 107 | |
| 96 |
Betty scored 92% on the test meaning she earned 92% of the possible points on the test. There were 300 possible points on the test so she earned 300 x 0.92 = 276 points. Each question is worth 3 points so she got \( \frac{276}{3} \) = 92 questions right.
A bread recipe calls for 2\(\frac{7}{8}\) cups of flour. If you only have \(\frac{5}{8}\) cup, how much more flour is needed?
| 1\(\frac{7}{8}\) cups | |
| \(\frac{5}{8}\) cups | |
| 2\(\frac{1}{4}\) cups | |
| 1\(\frac{1}{2}\) cups |
The amount of flour you need is (2\(\frac{7}{8}\) - \(\frac{5}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{23}{8} \) - \( \frac{5}{8} \)) cups
\( \frac{18}{8} \) cups
2\(\frac{1}{4}\) cups
Find the average of the following numbers: 11, 5, 11, 5.
| 3 | |
| 11 | |
| 8 | |
| 6 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{11 + 5 + 11 + 5}{4} \) = \( \frac{32}{4} \) = 8
If \( \left|c + 1\right| \) + 7 = -8, which of these is a possible value for c?
| -2 | |
| 3 | |
| -16 | |
| -8 |
First, solve for \( \left|c + 1\right| \):
\( \left|c + 1\right| \) + 7 = -8
\( \left|c + 1\right| \) = -8 - 7
\( \left|c + 1\right| \) = -15
The value inside the absolute value brackets can be either positive or negative so (c + 1) must equal - 15 or --15 for \( \left|c + 1\right| \) to equal -15:
| c + 1 = -15 c = -15 - 1 c = -16 | c + 1 = 15 c = 15 - 1 c = 14 |
So, c = 14 or c = -16.