| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.68 |
| Score | 0% | 54% |
A triathlon course includes a 100m swim, a 20.6km bike ride, and a 8.9km run. What is the total length of the race course?
| 32.3km | |
| 29.6km | |
| 54.9km | |
| 41.4km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.1km + 20.6km + 8.9km
total distance = 29.6km
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for division |
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distributive property for multiplication |
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commutative property for division |
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commutative property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
What is 2\( \sqrt{6} \) x 7\( \sqrt{6} \)?
| 9\( \sqrt{36} \) | |
| 14\( \sqrt{6} \) | |
| 84 | |
| 14\( \sqrt{12} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
2\( \sqrt{6} \) x 7\( \sqrt{6} \)
(2 x 7)\( \sqrt{6 \times 6} \)
14\( \sqrt{36} \)
Now we need to simplify the radical:
14\( \sqrt{36} \)
14\( \sqrt{6^2} \)
(14)(6)
84
A circular logo is enlarged to fit the lid of a jar. The new diameter is 40% larger than the original. By what percentage has the area of the logo increased?
| 35% | |
| 27\(\frac{1}{2}\)% | |
| 37\(\frac{1}{2}\)% | |
| 20% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 40% the radius (and, consequently, the total area) increases by \( \frac{40\text{%}}{2} \) = 20%
Solve 5 + (3 + 5) ÷ 2 x 2 - 32
| 1\(\frac{1}{3}\) | |
| 2 | |
| 4 | |
| 1 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
5 + (3 + 5) ÷ 2 x 2 - 32
P: 5 + (8) ÷ 2 x 2 - 32
E: 5 + 8 ÷ 2 x 2 - 9
MD: 5 + \( \frac{8}{2} \) x 2 - 9
MD: 5 + \( \frac{16}{2} \) - 9
AS: \( \frac{10}{2} \) + \( \frac{16}{2} \) - 9
AS: \( \frac{26}{2} \) - 9
AS: \( \frac{26 - 18}{2} \)
\( \frac{8}{2} \)
4