ASVAB Arithmetic Reasoning Practice Test 316338 Results

Your Results Global Average
Questions 5 5
Correct 0 2.91
Score 0% 58%

Review

1

A circular logo is enlarged to fit the lid of a jar. The new diameter is 75% larger than the original. By what percentage has the area of the logo increased?

51% Answer Correctly
20%
25%
22\(\frac{1}{2}\)%
37\(\frac{1}{2}\)%

Solution

The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 75% the radius (and, consequently, the total area) increases by \( \frac{75\text{%}}{2} \) = 37\(\frac{1}{2}\)%


2

A machine in a factory has an error rate of 9 parts per 100. The machine normally runs 24 hours a day and produces 6 parts per hour. Yesterday the machine was shut down for 8 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
186.2
149
87.4
179.6

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{9}{100} \) x 6 = \( \frac{9 \times 6}{100} \) = \( \frac{54}{100} \) = 0.54 errors per hour

So, in an average hour, the machine will produce 6 - 0.54 = 5.46 error free parts.

The machine ran for 24 - 8 = 16 hours yesterday so you would expect that 16 x 5.46 = 87.4 error free parts were produced yesterday.


3

What is \( \frac{9}{5} \) - \( \frac{8}{9} \)?

61% Answer Correctly
\(\frac{41}{45}\)
1 \( \frac{5}{45} \)
2 \( \frac{4}{45} \)
2 \( \frac{6}{45} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 5 and 9 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{9 x 9}{5 x 9} \) - \( \frac{8 x 5}{9 x 5} \)

\( \frac{81}{45} \) - \( \frac{40}{45} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{81 - 40}{45} \) = \( \frac{41}{45} \) = \(\frac{41}{45}\)


4

What is \( \frac{-6z^6}{8z^2} \)?

60% Answer Correctly
-1\(\frac{1}{3}\)z-4
-\(\frac{3}{4}\)z12
-1\(\frac{1}{3}\)z8
-\(\frac{3}{4}\)z4

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-6z^6}{8z^2} \)
\( \frac{-6}{8} \) z(6 - 2)
-\(\frac{3}{4}\)z4


5

What is \( \sqrt{\frac{49}{25}} \)?

70% Answer Correctly
2\(\frac{1}{2}\)
1
1\(\frac{1}{4}\)
1\(\frac{2}{5}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{49}{25}} \)
\( \frac{\sqrt{49}}{\sqrt{25}} \)
\( \frac{\sqrt{7^2}}{\sqrt{5^2}} \)
\( \frac{7}{5} \)
1\(\frac{2}{5}\)