ASVAB Arithmetic Reasoning Practice Test 316340 Results

Your Results Global Average
Questions 5 5
Correct 0 3.02
Score 0% 60%

Review

1

What is \( \frac{8}{3} \) - \( \frac{7}{9} \)?

61% Answer Correctly
1 \( \frac{7}{9} \)
1\(\frac{8}{9}\)
2 \( \frac{2}{9} \)
2 \( \frac{3}{9} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [9, 18, 27, 36, 45] making 9 the smallest multiple 3 and 9 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{8 x 3}{3 x 3} \) - \( \frac{7 x 1}{9 x 1} \)

\( \frac{24}{9} \) - \( \frac{7}{9} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{24 - 7}{9} \) = \( \frac{17}{9} \) = 1\(\frac{8}{9}\)


2

53% Answer Correctly
1.0
0.9
2.8
1

Solution


1


3

Which of the following is not an integer?

77% Answer Correctly

1

\({1 \over 2}\)

0

-1


Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.


4

What is \( 8 \)\( \sqrt{8} \) - \( 6 \)\( \sqrt{2} \)

38% Answer Correctly
2\( \sqrt{8} \)
10\( \sqrt{2} \)
48\( \sqrt{2} \)
2\( \sqrt{16} \)

Solution

To subtract these radicals together their radicands must be the same:

8\( \sqrt{8} \) - 6\( \sqrt{2} \)
8\( \sqrt{4 \times 2} \) - 6\( \sqrt{2} \)
8\( \sqrt{2^2 \times 2} \) - 6\( \sqrt{2} \)
(8)(2)\( \sqrt{2} \) - 6\( \sqrt{2} \)
16\( \sqrt{2} \) - 6\( \sqrt{2} \)

Now that the radicands are identical, you can subtract them:

16\( \sqrt{2} \) - 6\( \sqrt{2} \)
(16 - 6)\( \sqrt{2} \)
10\( \sqrt{2} \)


5

What is \( \frac{4}{9} \) ÷ \( \frac{4}{6} \)?

68% Answer Correctly
\(\frac{2}{3}\)
\(\frac{2}{27}\)
\(\frac{1}{12}\)
2\(\frac{2}{3}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{4}{9} \) ÷ \( \frac{4}{6} \) = \( \frac{4}{9} \) x \( \frac{6}{4} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{9} \) x \( \frac{6}{4} \) = \( \frac{4 x 6}{9 x 4} \) = \( \frac{24}{36} \) = \(\frac{2}{3}\)