ASVAB Arithmetic Reasoning Practice Test 323893 Results

Your Results Global Average
Questions 5 5
Correct 0 3.17
Score 0% 63%

Review

1

4! = ?

85% Answer Correctly

5 x 4 x 3 x 2 x 1

4 x 3

3 x 2 x 1

4 x 3 x 2 x 1


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


2

A bread recipe calls for 3 cups of flour. If you only have 1\(\frac{1}{8}\) cups, how much more flour is needed?

62% Answer Correctly
1\(\frac{7}{8}\) cups
2\(\frac{1}{8}\) cups
1\(\frac{5}{8}\) cups
1\(\frac{1}{4}\) cups

Solution

The amount of flour you need is (3 - 1\(\frac{1}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{24}{8} \) - \( \frac{9}{8} \)) cups
\( \frac{15}{8} \) cups
1\(\frac{7}{8}\) cups


3

How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 25 gallon tank to fill it exactly halfway?

52% Answer Correctly
9
10
5
7

Solution

To fill a 25 gallon tank exactly halfway you'll need 12\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:

cans = \( \frac{12\frac{1}{2} \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 5


4

The total water usage for a city is 35,000 gallons each day. Of that total, 22% is for personal use and 52% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?

58% Answer Correctly
2,500
4,750
3,400
10,500

Solution

52% of the water consumption is industrial use and 22% is personal use so (52% - 22%) = 30% more water is used for industrial purposes. 35,000 gallons are consumed daily so industry consumes \( \frac{30}{100} \) x 35,000 gallons = 10,500 gallons.


5

What is \( \frac{4}{4} \) + \( \frac{4}{8} \)?

60% Answer Correctly
\( \frac{2}{10} \)
2 \( \frac{7}{11} \)
1\(\frac{1}{2}\)
\( \frac{1}{8} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [8, 16, 24, 32, 40] making 8 the smallest multiple 4 and 8 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{4 x 2}{4 x 2} \) + \( \frac{4 x 1}{8 x 1} \)

\( \frac{8}{8} \) + \( \frac{4}{8} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{8 + 4}{8} \) = \( \frac{12}{8} \) = 1\(\frac{1}{2}\)