ASVAB Arithmetic Reasoning Practice Test 324001 Results

Your Results Global Average
Questions 5 5
Correct 0 2.99
Score 0% 60%

Review

1

Which of the following statements about exponents is false?

47% Answer Correctly

b1 = 1

b0 = 1

b1 = b

all of these are false


Solution

A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).


2

Which of these numbers is a factor of 48?

68% Answer Correctly
3
11
14
5

Solution

The factors of a number are all positive integers that divide evenly into the number. The factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.


3

What is the distance in miles of a trip that takes 4 hours at an average speed of 25 miles per hour?

87% Answer Correctly
100 miles
175 miles
375 miles
300 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 25mph \times 4h \)
100 miles


4

What is \( 7 \)\( \sqrt{112} \) - \( 9 \)\( \sqrt{7} \)

38% Answer Correctly
19\( \sqrt{7} \)
63\( \sqrt{112} \)
-2\( \sqrt{16} \)
63\( \sqrt{7} \)

Solution

To subtract these radicals together their radicands must be the same:

7\( \sqrt{112} \) - 9\( \sqrt{7} \)
7\( \sqrt{16 \times 7} \) - 9\( \sqrt{7} \)
7\( \sqrt{4^2 \times 7} \) - 9\( \sqrt{7} \)
(7)(4)\( \sqrt{7} \) - 9\( \sqrt{7} \)
28\( \sqrt{7} \) - 9\( \sqrt{7} \)

Now that the radicands are identical, you can subtract them:

28\( \sqrt{7} \) - 9\( \sqrt{7} \)
(28 - 9)\( \sqrt{7} \)
19\( \sqrt{7} \)


5

What is \( \frac{6}{3} \) - \( \frac{9}{9} \)?

61% Answer Correctly
2 \( \frac{4}{9} \)
1 \( \frac{1}{9} \)
1
2 \( \frac{6}{15} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [9, 18, 27, 36, 45] making 9 the smallest multiple 3 and 9 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{6 x 3}{3 x 3} \) - \( \frac{9 x 1}{9 x 1} \)

\( \frac{18}{9} \) - \( \frac{9}{9} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{18 - 9}{9} \) = \( \frac{9}{9} \) = 1