ASVAB Arithmetic Reasoning Practice Test 325753 Results

Your Results Global Average
Questions 5 5
Correct 0 2.92
Score 0% 58%

Review

1

What is \( \frac{-4a^5}{2a^2} \)?

60% Answer Correctly
-2a10
-2a-3
-\(\frac{1}{2}\)a-3
-2a3

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-4a^5}{2a^2} \)
\( \frac{-4}{2} \) a(5 - 2)
-2a3


2

If \( \left|y - 2\right| \) + 4 = 9, which of these is a possible value for y?

62% Answer Correctly
20
13
-5
-3

Solution

First, solve for \( \left|y - 2\right| \):

\( \left|y - 2\right| \) + 4 = 9
\( \left|y - 2\right| \) = 9 - 4
\( \left|y - 2\right| \) = 5

The value inside the absolute value brackets can be either positive or negative so (y - 2) must equal + 5 or -5 for \( \left|y - 2\right| \) to equal 5:

y - 2 = 5
y = 5 + 2
y = 7
y - 2 = -5
y = -5 + 2
y = -3

So, y = -3 or y = 7.


3

If the ratio of home fans to visiting fans in a crowd is 2:1 and all 35,000 seats in a stadium are filled, how many home fans are in attendance?

50% Answer Correctly
34,400
23,333
28,667
25,833

Solution

A ratio of 2:1 means that there are 2 home fans for every one visiting fan. So, of every 3 fans, 2 are home fans and \( \frac{2}{3} \) of every fan in the stadium is a home fan:

35,000 fans x \( \frac{2}{3} \) = \( \frac{70000}{3} \) = 23,333 fans.


4

Roger loaned Alex $1,300 at an annual interest rate of 4%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$28
$52
$135
$30

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,300
i = 0.04 x $1,300
i = $52


5

If a rectangle is twice as long as it is wide and has a perimeter of 48 meters, what is the area of the rectangle?

47% Answer Correctly
50 m2
128 m2
98 m2
8 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 48 meters so the equation becomes: 2w + 2h = 48.

Putting these two equations together and solving for width (w):

2w + 2h = 48
w + h = \( \frac{48}{2} \)
w + h = 24
w = 24 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 24 - 2w
3w = 24
w = \( \frac{24}{3} \)
w = 8

Since h = 2w that makes h = (2 x 8) = 16 and the area = h x w = 8 x 16 = 128 m2