| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.52 |
| Score | 0% | 70% |
Which of the following is a mixed number?
\({5 \over 7} \) |
|
\({a \over 5} \) |
|
\({7 \over 5} \) |
|
\(1 {2 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
How many 15-passenger vans will it take to drive all 51 members of the football team to an away game?
| 5 vans | |
| 14 vans | |
| 6 vans | |
| 4 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{51}{15} \) = 3\(\frac{2}{5}\)
So, it will take 3 full vans and one partially full van to transport the entire team making a total of 4 vans.
What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?
| 35 | |
| 30 | |
| 31 | |
| 36 |
The equation for this sequence is:
an = an-1 + 2(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31
If the ratio of home fans to visiting fans in a crowd is 5:1 and all 31,000 seats in a stadium are filled, how many home fans are in attendance?
| 24,000 | |
| 27,750 | |
| 31,200 | |
| 25,833 |
A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:
31,000 fans x \( \frac{5}{6} \) = \( \frac{155000}{6} \) = 25,833 fans.
Convert z-5 to remove the negative exponent.
| \( \frac{1}{z^5} \) | |
| \( \frac{-1}{z^{-5}} \) | |
| \( \frac{1}{z^{-5}} \) | |
| \( \frac{-1}{-5z} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.