ASVAB Arithmetic Reasoning Practice Test 327164 Results

Your Results Global Average
Questions 5 5
Correct 0 3.05
Score 0% 61%

Review

1

Simplify \( \sqrt{125} \)

62% Answer Correctly
4\( \sqrt{5} \)
6\( \sqrt{10} \)
5\( \sqrt{5} \)
8\( \sqrt{10} \)

Solution

To simplify a radical, factor out the perfect squares:

\( \sqrt{125} \)
\( \sqrt{25 \times 5} \)
\( \sqrt{5^2 \times 5} \)
5\( \sqrt{5} \)


2

What is \( \frac{2}{7} \) ÷ \( \frac{1}{8} \)?

68% Answer Correctly
\(\frac{9}{56}\)
\(\frac{1}{20}\)
2\(\frac{2}{7}\)
16

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{2}{7} \) ÷ \( \frac{1}{8} \) = \( \frac{2}{7} \) x \( \frac{8}{1} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{7} \) x \( \frac{8}{1} \) = \( \frac{2 x 8}{7 x 1} \) = \( \frac{16}{7} \) = 2\(\frac{2}{7}\)


3

Which of the following statements about exponents is false?

47% Answer Correctly

b1 = 1

all of these are false

b0 = 1

b1 = b


Solution

A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).


4

What is \( \frac{1}{9} \) x \( \frac{2}{9} \)?

72% Answer Correctly
\(\frac{2}{9}\)
\(\frac{3}{14}\)
\(\frac{1}{16}\)
\(\frac{2}{81}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{1}{9} \) x \( \frac{2}{9} \) = \( \frac{1 x 2}{9 x 9} \) = \( \frac{2}{81} \) = \(\frac{2}{81}\)


5

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

distributive property for division

commutative property for division

commutative property for multiplication

distributive property for multiplication


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).