| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.05 |
| Score | 0% | 61% |
Simplify \( \sqrt{125} \)
| 4\( \sqrt{5} \) | |
| 6\( \sqrt{10} \) | |
| 5\( \sqrt{5} \) | |
| 8\( \sqrt{10} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{125} \)
\( \sqrt{25 \times 5} \)
\( \sqrt{5^2 \times 5} \)
5\( \sqrt{5} \)
What is \( \frac{2}{7} \) ÷ \( \frac{1}{8} \)?
| \(\frac{9}{56}\) | |
| \(\frac{1}{20}\) | |
| 2\(\frac{2}{7}\) | |
| 16 |
To divide fractions, invert the second fraction and then multiply:
\( \frac{2}{7} \) ÷ \( \frac{1}{8} \) = \( \frac{2}{7} \) x \( \frac{8}{1} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{7} \) x \( \frac{8}{1} \) = \( \frac{2 x 8}{7 x 1} \) = \( \frac{16}{7} \) = 2\(\frac{2}{7}\)
Which of the following statements about exponents is false?
b1 = 1 |
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all of these are false |
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b0 = 1 |
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b1 = b |
A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).
What is \( \frac{1}{9} \) x \( \frac{2}{9} \)?
| \(\frac{2}{9}\) | |
| \(\frac{3}{14}\) | |
| \(\frac{1}{16}\) | |
| \(\frac{2}{81}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{1}{9} \) x \( \frac{2}{9} \) = \( \frac{1 x 2}{9 x 9} \) = \( \frac{2}{81} \) = \(\frac{2}{81}\)
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for division |
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commutative property for division |
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commutative property for multiplication |
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distributive property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).