ASVAB Arithmetic Reasoning Practice Test 327393 Results

Your Results Global Average
Questions 5 5
Correct 0 3.35
Score 0% 67%

Review

1

What is \( \frac{4}{6} \) ÷ \( \frac{3}{9} \)?

68% Answer Correctly
2
\(\frac{1}{12}\)
\(\frac{1}{5}\)
\(\frac{4}{15}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{4}{6} \) ÷ \( \frac{3}{9} \) = \( \frac{4}{6} \) x \( \frac{9}{3} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{6} \) x \( \frac{9}{3} \) = \( \frac{4 x 9}{6 x 3} \) = \( \frac{36}{18} \) = 2


2

If \( \left|y - 2\right| \) - 1 = -8, which of these is a possible value for y?

62% Answer Correctly
22
-9
10
9

Solution

First, solve for \( \left|y - 2\right| \):

\( \left|y - 2\right| \) - 1 = -8
\( \left|y - 2\right| \) = -8 + 1
\( \left|y - 2\right| \) = -7

The value inside the absolute value brackets can be either positive or negative so (y - 2) must equal - 7 or --7 for \( \left|y - 2\right| \) to equal -7:

y - 2 = -7
y = -7 + 2
y = -5
y - 2 = 7
y = 7 + 2
y = 9

So, y = 9 or y = -5.


3

What is the least common multiple of 5 and 7?

72% Answer Correctly
10
7
35
27

Solution

The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [35, 70] making 35 the smallest multiple 5 and 7 have in common.


4

If there were a total of 250 raffle tickets sold and you bought 17 tickets, what's the probability that you'll win the raffle?

60% Answer Correctly
15%
1%
9%
7%

Solution

You have 17 out of the total of 250 raffle tickets sold so you have a (\( \frac{17}{250} \)) x 100 = \( \frac{17 \times 100}{250} \) = \( \frac{1700}{250} \) = 7% chance to win the raffle.


5

What is \( \frac{1}{8} \) x \( \frac{3}{7} \)?

72% Answer Correctly
\(\frac{3}{8}\)
\(\frac{4}{27}\)
\(\frac{3}{7}\)
\(\frac{3}{56}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{1}{8} \) x \( \frac{3}{7} \) = \( \frac{1 x 3}{8 x 7} \) = \( \frac{3}{56} \) = \(\frac{3}{56}\)