To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 11 are [11, 22, 33, 44, 55, 66, 77, 88, 99]. The first few multiples they share are [33, 66, 99] making 33 the smallest multiple 3 and 11 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{7 x 11}{3 x 11} \) + \( \frac{5 x 3}{11 x 3} \)

\( \frac{77}{33} \) + \( \frac{15}{33} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{77 + 15}{33} \) = \( \frac{92}{33} \) = 2\(\frac{71}{90}\)

The factors of 32 are [1, 2, 4, 8, 16, 32] and the factors of 72 are [1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72]. They share 4 factors [1, 2, 4, 8] making 8 the greatest factor 32 and 72 have in common.

The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 4 and 6 have in common.

The amount of flour you need is (3\(\frac{1}{8}\) - \(\frac{3}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{25}{8} \) - \( \frac{3}{8} \)) cups
\( \frac{22}{8} \) cups
2\(\frac{3}{4}\) cups