ASVAB Arithmetic Reasoning Practice Test 329176 Results

Your Results Global Average
Questions 5 5
Correct 0 2.99
Score 0% 60%

Review

1

Which of the following is an improper fraction?

70% Answer Correctly

\(1 {2 \over 5} \)

\({2 \over 5} \)

\({7 \over 5} \)

\({a \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


2

A circular logo is enlarged to fit the lid of a jar. The new diameter is 75% larger than the original. By what percentage has the area of the logo increased?

50% Answer Correctly
25%
37\(\frac{1}{2}\)%
27\(\frac{1}{2}\)%
15%

Solution

The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 75% the radius (and, consequently, the total area) increases by \( \frac{75\text{%}}{2} \) = 37\(\frac{1}{2}\)%


3

What is \( \frac{1y^5}{7y^2} \)?

60% Answer Correctly
7y-3
\(\frac{1}{7}\)y7
\(\frac{1}{7}\)y3
\(\frac{1}{7}\)y\(\frac{2}{5}\)

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{y^5}{7y^2} \)
\( \frac{1}{7} \) y(5 - 2)
\(\frac{1}{7}\)y3


4

What is \( \frac{2}{4} \) + \( \frac{8}{8} \)?

59% Answer Correctly
2 \( \frac{1}{8} \)
2 \( \frac{3}{8} \)
1 \( \frac{2}{11} \)
1\(\frac{1}{2}\)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [8, 16, 24, 32, 40] making 8 the smallest multiple 4 and 8 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{2 x 2}{4 x 2} \) + \( \frac{8 x 1}{8 x 1} \)

\( \frac{4}{8} \) + \( \frac{8}{8} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{4 + 8}{8} \) = \( \frac{12}{8} \) = 1\(\frac{1}{2}\)


5

Christine scored 88% on her final exam. If each question was worth 3 points and there were 180 possible points on the exam, how many questions did Christine answer correctly?

57% Answer Correctly
57
50
45
53

Solution

Christine scored 88% on the test meaning she earned 88% of the possible points on the test. There were 180 possible points on the test so she earned 180 x 0.88 = 159 points. Each question is worth 3 points so she got \( \frac{159}{3} \) = 53 questions right.