| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.99 |
| Score | 0% | 60% |
Which of the following is an improper fraction?
\(1 {2 \over 5} \) |
|
\({2 \over 5} \) |
|
\({7 \over 5} \) |
|
\({a \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
A circular logo is enlarged to fit the lid of a jar. The new diameter is 75% larger than the original. By what percentage has the area of the logo increased?
| 25% | |
| 37\(\frac{1}{2}\)% | |
| 27\(\frac{1}{2}\)% | |
| 15% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 75% the radius (and, consequently, the total area) increases by \( \frac{75\text{%}}{2} \) = 37\(\frac{1}{2}\)%
What is \( \frac{1y^5}{7y^2} \)?
| 7y-3 | |
| \(\frac{1}{7}\)y7 | |
| \(\frac{1}{7}\)y3 | |
| \(\frac{1}{7}\)y\(\frac{2}{5}\) |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{y^5}{7y^2} \)
\( \frac{1}{7} \) y(5 - 2)
\(\frac{1}{7}\)y3
What is \( \frac{2}{4} \) + \( \frac{8}{8} \)?
| 2 \( \frac{1}{8} \) | |
| 2 \( \frac{3}{8} \) | |
| 1 \( \frac{2}{11} \) | |
| 1\(\frac{1}{2}\) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [8, 16, 24, 32, 40] making 8 the smallest multiple 4 and 8 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{2 x 2}{4 x 2} \) + \( \frac{8 x 1}{8 x 1} \)
\( \frac{4}{8} \) + \( \frac{8}{8} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{4 + 8}{8} \) = \( \frac{12}{8} \) = 1\(\frac{1}{2}\)
Christine scored 88% on her final exam. If each question was worth 3 points and there were 180 possible points on the exam, how many questions did Christine answer correctly?
| 57 | |
| 50 | |
| 45 | |
| 53 |
Christine scored 88% on the test meaning she earned 88% of the possible points on the test. There were 180 possible points on the test so she earned 180 x 0.88 = 159 points. Each question is worth 3 points so she got \( \frac{159}{3} \) = 53 questions right.