ASVAB Arithmetic Reasoning Practice Test 329415 Results

Your Results Global Average
Questions 5 5
Correct 0 3.48
Score 0% 70%

Review

1

Which of the following is a mixed number?

82% Answer Correctly

\({7 \over 5} \)

\({a \over 5} \)

\(1 {2 \over 5} \)

\({5 \over 7} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


2

Which of the following is not an integer?

77% Answer Correctly

\({1 \over 2}\)

1

-1

0


Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.


3

What is the next number in this sequence: 1, 4, 10, 19, 31, __________ ?

69% Answer Correctly
46
48
43
40

Solution

The equation for this sequence is:

an = an-1 + 3(n - 1)

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 3(6 - 1)
a6 = 31 + 3(5)
a6 = 46


4

How many 9-passenger vans will it take to drive all 82 members of the football team to an away game?

80% Answer Correctly
6 vans
8 vans
10 vans
7 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{82}{9} \) = 9\(\frac{1}{9}\)

So, it will take 9 full vans and one partially full van to transport the entire team making a total of 10 vans.


5

What is \( 4 \)\( \sqrt{112} \) + \( 7 \)\( \sqrt{7} \)

35% Answer Correctly
28\( \sqrt{16} \)
28\( \sqrt{784} \)
28\( \sqrt{112} \)
23\( \sqrt{7} \)

Solution

To add these radicals together their radicands must be the same:

4\( \sqrt{112} \) + 7\( \sqrt{7} \)
4\( \sqrt{16 \times 7} \) + 7\( \sqrt{7} \)
4\( \sqrt{4^2 \times 7} \) + 7\( \sqrt{7} \)
(4)(4)\( \sqrt{7} \) + 7\( \sqrt{7} \)
16\( \sqrt{7} \) + 7\( \sqrt{7} \)

Now that the radicands are identical, you can add them together:

16\( \sqrt{7} \) + 7\( \sqrt{7} \)
(16 + 7)\( \sqrt{7} \)
23\( \sqrt{7} \)