ASVAB Arithmetic Reasoning Practice Test 330068 Results

Your Results Global Average
Questions 5 5
Correct 0 3.04
Score 0% 61%

Review

1

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 25% off." If Damon buys two shirts, each with a regular price of $49, how much will he pay for both shirts?

56% Answer Correctly
$61.25
$36.75
$85.75
$56.35

Solution

By buying two shirts, Damon will save $49 x \( \frac{25}{100} \) = \( \frac{$49 x 25}{100} \) = \( \frac{$1225}{100} \) = $12.25 on the second shirt.

So, his total cost will be
$49.00 + ($49.00 - $12.25)
$49.00 + $36.75
$85.75


2

Which of the following is an improper fraction?

71% Answer Correctly

\({a \over 5} \)

\({2 \over 5} \)

\(1 {2 \over 5} \)

\({7 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


3

Solve for \( \frac{4!}{5!} \)

67% Answer Correctly
8
\( \frac{1}{5} \)
60480
\( \frac{1}{1680} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{4!}{5!} \)
\( \frac{4 \times 3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5} \)
\( \frac{1}{5} \)


4

Which of the following is not a prime number?

65% Answer Correctly

7

5

2

9


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


5

On average, the center for a basketball team hits 40% of his shots while a guard on the same team hits 55% of his shots. If the guard takes 30 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?

42% Answer Correctly
35
40
31
33

Solution
If the guard hits 55% of his shots and takes 30 shots he'll make:

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 30 x \( \frac{55}{100} \) = \( \frac{55 x 30}{100} \) = \( \frac{1650}{100} \) = 16 shots

The center makes 40% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{16}{\frac{40}{100}} \) = 16 x \( \frac{100}{40} \) = \( \frac{16 x 100}{40} \) = \( \frac{1600}{40} \) = 40 shots

to make the same number of shots as the guard and thus score the same number of points.