ASVAB Arithmetic Reasoning Practice Test 331615 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.22
Score	0%	64%

Review

Which of the following is not an integer?

77% Answer Correctly

	1
	0
	${1 \over 2}$
	-1

Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.

What is $ \sqrt{\frac{9}{16}} $?

70% Answer Correctly

	$\frac{3}{4}$
	$\frac{5}{9}$
	1$\frac{1}{2}$
	$\frac{2}{3}$

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

$ \sqrt{\frac{9}{16}} $
$ \frac{\sqrt{9}}{\sqrt{16}} $
$ \frac{\sqrt{3^2}}{\sqrt{4^2}} $
$\frac{3}{4}$

Alex loaned Monica $900 at an annual interest rate of 3%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly

	$927
	$945
	$972
	$981

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = ($ \frac{6}{100} $) x $900
i = 0.03 x $900

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $900 + $27
total = $927

In a class of 23 students, 12 are taking German and 6 are taking Spanish. Of the students studying German or Spanish, 6 are taking both courses. How many students are not enrolled in either course?

63% Answer Correctly

	11
	21
	10
	20

Solution

The number of students taking German or Spanish is 12 + 6 = 18. Of that group of 18, 6 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 18 - 6 = 12 who are taking at least one language. 23 - 12 = 11 students who are not taking either language.

What is $ 4 $$ \sqrt{8} $ - $ 6 $$ \sqrt{2} $

38% Answer Correctly

	24$ \sqrt{8} $
	2$ \sqrt{2} $
	-2$ \sqrt{4} $
	-2$ \sqrt{2} $

Solution

To subtract these radicals together their radicands must be the same:

4$ \sqrt{8} $ - 6$ \sqrt{2} $
4$ \sqrt{4 \times 2} $ - 6$ \sqrt{2} $
4$ \sqrt{2^2 \times 2} $ - 6$ \sqrt{2} $
(4)(2)$ \sqrt{2} $ - 6$ \sqrt{2} $
8$ \sqrt{2} $ - 6$ \sqrt{2} $

Now that the radicands are identical, you can subtract them:

8$ \sqrt{2} $ - 6$ \sqrt{2} $
(8 - 6)$ \sqrt{2} $
2$ \sqrt{2} $

	\(\frac{3}{4}\)
	\(\frac{5}{9}\)
	1\(\frac{1}{2}\)
	\(\frac{2}{3}\)

	24\( \sqrt{8} \)
	2\( \sqrt{2} \)
	-2\( \sqrt{4} \)
	-2\( \sqrt{2} \)

	1
	0
	\({1 \over 2}\)
	-1