| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.12 |
| Score | 0% | 62% |
A tiger in a zoo has consumed 48 pounds of food in 4 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 120 pounds?
| 6 | |
| 68 | |
| 1 | |
| 3 |
If the tiger has consumed 48 pounds of food in 4 days that's \( \frac{48}{4} \) = 12 pounds of food per day. The tiger needs to consume 120 - 48 = 72 more pounds of food to reach 120 pounds total. At 12 pounds of food per day that's \( \frac{72}{12} \) = 6 more days.
How many hours does it take a car to travel 245 miles at an average speed of 35 miles per hour?
| 1 hour | |
| 5 hours | |
| 8 hours | |
| 7 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{245mi}{35mph} \)
7 hours
What is \( 4 \)\( \sqrt{112} \) + \( 8 \)\( \sqrt{7} \)
| 12\( \sqrt{784} \) | |
| 12\( \sqrt{112} \) | |
| 24\( \sqrt{7} \) | |
| 32\( \sqrt{112} \) |
To add these radicals together their radicands must be the same:
4\( \sqrt{112} \) + 8\( \sqrt{7} \)
4\( \sqrt{16 \times 7} \) + 8\( \sqrt{7} \)
4\( \sqrt{4^2 \times 7} \) + 8\( \sqrt{7} \)
(4)(4)\( \sqrt{7} \) + 8\( \sqrt{7} \)
16\( \sqrt{7} \) + 8\( \sqrt{7} \)
Now that the radicands are identical, you can add them together:
16\( \sqrt{7} \) + 8\( \sqrt{7} \)If \( \left|a + 6\right| \) + 8 = 1, which of these is a possible value for a?
| 1 | |
| -5 | |
| -6 | |
| 0 |
First, solve for \( \left|a + 6\right| \):
\( \left|a + 6\right| \) + 8 = 1
\( \left|a + 6\right| \) = 1 - 8
\( \left|a + 6\right| \) = -7
The value inside the absolute value brackets can be either positive or negative so (a + 6) must equal - 7 or --7 for \( \left|a + 6\right| \) to equal -7:
| a + 6 = -7 a = -7 - 6 a = -13 | a + 6 = 7 a = 7 - 6 a = 1 |
So, a = 1 or a = -13.
What is \( \frac{3}{6} \) x \( \frac{4}{9} \)?
| 2 | |
| \(\frac{1}{12}\) | |
| \(\frac{2}{25}\) | |
| \(\frac{2}{9}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{6} \) x \( \frac{4}{9} \) = \( \frac{3 x 4}{6 x 9} \) = \( \frac{12}{54} \) = \(\frac{2}{9}\)