| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.26 |
| Score | 0% | 65% |
This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
PEDMAS |
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associative |
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distributive |
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commutative |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
What is the distance in miles of a trip that takes 2 hours at an average speed of 15 miles per hour?
| 140 miles | |
| 30 miles | |
| 630 miles | |
| 100 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 15mph \times 2h \)
30 miles
Latoya scored 93% on her final exam. If each question was worth 2 points and there were 60 possible points on the exam, how many questions did Latoya answer correctly?
| 43 | |
| 38 | |
| 27 | |
| 28 |
Latoya scored 93% on the test meaning she earned 93% of the possible points on the test. There were 60 possible points on the test so she earned 60 x 0.93 = 56 points. Each question is worth 2 points so she got \( \frac{56}{2} \) = 28 questions right.
In a class of 21 students, 9 are taking German and 7 are taking Spanish. Of the students studying German or Spanish, 4 are taking both courses. How many students are not enrolled in either course?
| 17 | |
| 10 | |
| 9 | |
| 14 |
The number of students taking German or Spanish is 9 + 7 = 16. Of that group of 16, 4 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 16 - 4 = 12 who are taking at least one language. 21 - 12 = 9 students who are not taking either language.
What is \( \frac{8a^6}{5a^2} \)?
| 1\(\frac{3}{5}\)a3 | |
| 1\(\frac{3}{5}\)a12 | |
| 1\(\frac{3}{5}\)a4 | |
| \(\frac{5}{8}\)a-4 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{8a^6}{5a^2} \)
\( \frac{8}{5} \) a(6 - 2)
1\(\frac{3}{5}\)a4