| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.52 |
| Score | 0% | 70% |
How many 1 gallon cans worth of fuel would you need to pour into an empty 4 gallon tank to fill it exactly halfway?
| 4 | |
| 2 | |
| 83 | |
| 7 |
To fill a 4 gallon tank exactly halfway you'll need 2 gallons of fuel. Each fuel can holds 1 gallons so:
cans = \( \frac{2 \text{ gallons}}{1 \text{ gallons}} \) = 2
What is (a2)3?
| a | |
| a6 | |
| 2a3 | |
| a5 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(a2)34! = ?
4 x 3 x 2 x 1 |
|
5 x 4 x 3 x 2 x 1 |
|
4 x 3 |
|
3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
In a class of 32 students, 9 are taking German and 14 are taking Spanish. Of the students studying German or Spanish, 6 are taking both courses. How many students are not enrolled in either course?
| 27 | |
| 29 | |
| 12 | |
| 15 |
The number of students taking German or Spanish is 9 + 14 = 23. Of that group of 23, 6 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 23 - 6 = 17 who are taking at least one language. 32 - 17 = 15 students who are not taking either language.
What is \( \frac{1}{9} \) x \( \frac{2}{8} \)?
| \(\frac{6}{35}\) | |
| \(\frac{2}{9}\) | |
| \(\frac{1}{36}\) | |
| \(\frac{1}{12}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{1}{9} \) x \( \frac{2}{8} \) = \( \frac{1 x 2}{9 x 8} \) = \( \frac{2}{72} \) = \(\frac{1}{36}\)