| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.36 |
| Score | 0% | 67% |
What is the distance in miles of a trip that takes 9 hours at an average speed of 40 miles per hour?
| 200 miles | |
| 360 miles | |
| 100 miles | |
| 45 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 40mph \times 9h \)
360 miles
What is (a2)5?
| a3 | |
| a7 | |
| 2a5 | |
| a10 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(a2)5What is \( \frac{12\sqrt{45}}{6\sqrt{9}} \)?
| 5 \( \sqrt{2} \) | |
| 2 \( \sqrt{5} \) | |
| 5 \( \sqrt{\frac{1}{2}} \) | |
| \(\frac{1}{5}\) \( \sqrt{2} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{12\sqrt{45}}{6\sqrt{9}} \)
\( \frac{12}{6} \) \( \sqrt{\frac{45}{9}} \)
2 \( \sqrt{5} \)
On average, the center for a basketball team hits 50% of his shots while a guard on the same team hits 55% of his shots. If the guard takes 15 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 19 | |
| 21 | |
| 29 | |
| 16 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{55}{100} \) = \( \frac{55 x 15}{100} \) = \( \frac{825}{100} \) = 8 shots
The center makes 50% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{8}{\frac{50}{100}} \) = 8 x \( \frac{100}{50} \) = \( \frac{8 x 100}{50} \) = \( \frac{800}{50} \) = 16 shots
to make the same number of shots as the guard and thus score the same number of points.
A tiger in a zoo has consumed 90 pounds of food in 9 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 120 pounds?
| 4 | |
| 3 | |
| 8 | |
| 12 |
If the tiger has consumed 90 pounds of food in 9 days that's \( \frac{90}{9} \) = 10 pounds of food per day. The tiger needs to consume 120 - 90 = 30 more pounds of food to reach 120 pounds total. At 10 pounds of food per day that's \( \frac{30}{10} \) = 3 more days.