| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.06 |
| Score | 0% | 61% |
Charlie loaned Roger $1,200 at an annual interest rate of 8%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $88 | |
| $49 | |
| $96 | |
| $80 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,200
i = 0.08 x $1,200
i = $96
The __________ is the greatest factor that divides two integers.
least common multiple |
|
greatest common multiple |
|
absolute value |
|
greatest common factor |
The greatest common factor (GCF) is the greatest factor that divides two integers.
What is \( \frac{2}{6} \) + \( \frac{9}{10} \)?
| 2 \( \frac{1}{30} \) | |
| 1 \( \frac{4}{9} \) | |
| 2 \( \frac{8}{30} \) | |
| 1\(\frac{7}{30}\) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [30, 60, 90] making 30 the smallest multiple 6 and 10 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{2 x 5}{6 x 5} \) + \( \frac{9 x 3}{10 x 3} \)
\( \frac{10}{30} \) + \( \frac{27}{30} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{10 + 27}{30} \) = \( \frac{37}{30} \) = 1\(\frac{7}{30}\)
On average, the center for a basketball team hits 35% of his shots while a guard on the same team hits 45% of his shots. If the guard takes 20 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 16 | |
| 24 | |
| 26 | |
| 21 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 20 x \( \frac{45}{100} \) = \( \frac{45 x 20}{100} \) = \( \frac{900}{100} \) = 9 shots
The center makes 35% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{9}{\frac{35}{100}} \) = 9 x \( \frac{100}{35} \) = \( \frac{9 x 100}{35} \) = \( \frac{900}{35} \) = 26 shots
to make the same number of shots as the guard and thus score the same number of points.
If \( \left|a - 6\right| \) - 6 = -9, which of these is a possible value for a?
| 9 | |
| -11 | |
| -8 | |
| -22 |
First, solve for \( \left|a - 6\right| \):
\( \left|a - 6\right| \) - 6 = -9
\( \left|a - 6\right| \) = -9 + 6
\( \left|a - 6\right| \) = -3
The value inside the absolute value brackets can be either positive or negative so (a - 6) must equal - 3 or --3 for \( \left|a - 6\right| \) to equal -3:
| a - 6 = -3 a = -3 + 6 a = 3 | a - 6 = 3 a = 3 + 6 a = 9 |
So, a = 9 or a = 3.