ASVAB Arithmetic Reasoning Practice Test 341519 Results

Your Results Global Average
Questions 5 5
Correct 0 3.60
Score 0% 72%

Review

1

What is \( \frac{5}{2} \) + \( \frac{6}{4} \)?

59% Answer Correctly
4
2 \( \frac{6}{15} \)
2 \( \frac{1}{4} \)
2 \( \frac{2}{10} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40]. The first few multiples they share are [4, 8, 12, 16, 20] making 4 the smallest multiple 2 and 4 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{5 x 2}{2 x 2} \) + \( \frac{6 x 1}{4 x 1} \)

\( \frac{10}{4} \) + \( \frac{6}{4} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{10 + 6}{4} \) = \( \frac{16}{4} \) = 4


2

What is b4 + 5b4?

66% Answer Correctly
6b-8
6b16
6b4
-4b-4

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

1b4 + 5b4
(1 + 5)b4
6b4


3

What is (z5)2?

79% Answer Correctly
z7
z10
z-3
2z5

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(z5)2
z(5 * 2)
z10


4

What is -5a6 - 9a6?

71% Answer Correctly
-14a6
14a6
4a-12
4a36

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

-5a6 - 9a6
(-5 - 9)a6
-14a6


5

What is the distance in miles of a trip that takes 9 hours at an average speed of 65 miles per hour?

86% Answer Correctly
20 miles
15 miles
180 miles
585 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 65mph \times 9h \)
585 miles