| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.48 |
| Score | 0% | 70% |
How many hours does it take a car to travel 130 miles at an average speed of 65 miles per hour?
| 2 hours | |
| 6 hours | |
| 9 hours | |
| 8 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{130mi}{65mph} \)
2 hours
What is the least common multiple of 8 and 12?
| 32 | |
| 24 | |
| 96 | |
| 49 |
The first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [24, 48, 72, 96] making 24 the smallest multiple 8 and 12 have in common.
5 members of a bridal party need transported to a wedding reception but there are only 2 2-passenger taxis available to take them. How many will need to find other transportation?
| 1 | |
| 2 | |
| 4 | |
| 8 |
There are 2 2-passenger taxis available so that's 2 x 2 = 4 total seats. There are 5 people needing transportation leaving 5 - 4 = 1 who will have to find other transportation.
If \( \left|y + 3\right| \) + 3 = -8, which of these is a possible value for y?
| 5 | |
| 1 | |
| -14 | |
| -22 |
First, solve for \( \left|y + 3\right| \):
\( \left|y + 3\right| \) + 3 = -8
\( \left|y + 3\right| \) = -8 - 3
\( \left|y + 3\right| \) = -11
The value inside the absolute value brackets can be either positive or negative so (y + 3) must equal - 11 or --11 for \( \left|y + 3\right| \) to equal -11:
| y + 3 = -11 y = -11 - 3 y = -14 | y + 3 = 11 y = 11 - 3 y = 8 |
So, y = 8 or y = -14.
If all of a roofing company's 6 workers are required to staff 2 roofing crews, how many workers need to be added during the busy season in order to send 6 complete crews out on jobs?
| 6 | |
| 1 | |
| 11 | |
| 12 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 6 workers at the company now and that's enough to staff 2 crews so there are \( \frac{6}{2} \) = 3 workers on a crew. 6 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 6 x 3 = 18 total workers to staff the crews during the busy season. The company already employs 6 workers so they need to add 18 - 6 = 12 new staff for the busy season.