ASVAB Arithmetic Reasoning Practice Test 342101 Results

Your Results Global Average
Questions 5 5
Correct 0 3.24
Score 0% 65%

Review

1

Which of the following is not a prime number?

65% Answer Correctly

2

5

7

9


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


2

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 5% off." If Charlie buys two shirts, each with a regular price of $26, how much money will he save?

70% Answer Correctly
$1.30
$2.60
$11.70
$6.50

Solution

By buying two shirts, Charlie will save $26 x \( \frac{5}{100} \) = \( \frac{$26 x 5}{100} \) = \( \frac{$130}{100} \) = $1.30 on the second shirt.


3

What is the distance in miles of a trip that takes 3 hours at an average speed of 50 miles per hour?

87% Answer Correctly
150 miles
120 miles
270 miles
140 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 50mph \times 3h \)
150 miles


4

A machine in a factory has an error rate of 2 parts per 100. The machine normally runs 24 hours a day and produces 6 parts per hour. Yesterday the machine was shut down for 9 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
176.7
69
85.5
88.2

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{2}{100} \) x 6 = \( \frac{2 \times 6}{100} \) = \( \frac{12}{100} \) = 0.12 errors per hour

So, in an average hour, the machine will produce 6 - 0.12 = 5.88 error free parts.

The machine ran for 24 - 9 = 15 hours yesterday so you would expect that 15 x 5.88 = 88.2 error free parts were produced yesterday.


5

If all of a roofing company's 6 workers are required to staff 3 roofing crews, how many workers need to be added during the busy season in order to send 5 complete crews out on jobs?

55% Answer Correctly
9
6
4
14

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 6 workers at the company now and that's enough to staff 3 crews so there are \( \frac{6}{3} \) = 2 workers on a crew. 5 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 5 x 2 = 10 total workers to staff the crews during the busy season. The company already employs 6 workers so they need to add 10 - 6 = 4 new staff for the busy season.