ASVAB Arithmetic Reasoning Practice Test 346517 Results

Your Results Global Average
Questions 5 5
Correct 0 3.08
Score 0% 62%

Review

1

What is \( 7 \)\( \sqrt{27} \) - \( 4 \)\( \sqrt{3} \)

38% Answer Correctly
3\( \sqrt{0} \)
17\( \sqrt{3} \)
3\( \sqrt{3} \)
28\( \sqrt{81} \)

Solution

To subtract these radicals together their radicands must be the same:

7\( \sqrt{27} \) - 4\( \sqrt{3} \)
7\( \sqrt{9 \times 3} \) - 4\( \sqrt{3} \)
7\( \sqrt{3^2 \times 3} \) - 4\( \sqrt{3} \)
(7)(3)\( \sqrt{3} \) - 4\( \sqrt{3} \)
21\( \sqrt{3} \) - 4\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

21\( \sqrt{3} \) - 4\( \sqrt{3} \)
(21 - 4)\( \sqrt{3} \)
17\( \sqrt{3} \)


2

What is \( \frac{49\sqrt{32}}{7\sqrt{8}} \)?

71% Answer Correctly
\(\frac{1}{4}\) \( \sqrt{7} \)
\(\frac{1}{4}\) \( \sqrt{\frac{1}{7}} \)
\(\frac{1}{7}\) \( \sqrt{\frac{1}{4}} \)
7 \( \sqrt{4} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{49\sqrt{32}}{7\sqrt{8}} \)
\( \frac{49}{7} \) \( \sqrt{\frac{32}{8}} \)
7 \( \sqrt{4} \)


3

Which of these numbers is a factor of 32?

69% Answer Correctly
16
14
4
27

Solution

The factors of a number are all positive integers that divide evenly into the number. The factors of 32 are 1, 2, 4, 8, 16, 32.


4

What is -8c6 x 6c4?

75% Answer Correctly
-48c2
-48c-2
-2c4
-48c10

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

-8c6 x 6c4
(-8 x 6)c(6 + 4)
-48c10


5

If all of a roofing company's 10 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?

55% Answer Correctly
14
13
4
8

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 10 workers at the company now and that's enough to staff 5 crews so there are \( \frac{10}{5} \) = 2 workers on a crew. 7 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 7 x 2 = 14 total workers to staff the crews during the busy season. The company already employs 10 workers so they need to add 14 - 10 = 4 new staff for the busy season.