ASVAB Arithmetic Reasoning Practice Test 346790 Results

Your Results Global Average
Questions 5 5
Correct 0 2.51
Score 0% 50%

Review

1

If a mayor is elected with 79% of the votes cast and 41% of a town's 44,000 voters cast a vote, how many votes did the mayor receive?

49% Answer Correctly
14,252
13,530
13,891
9,381

Solution

If 41% of the town's 44,000 voters cast ballots the number of votes cast is:

(\( \frac{41}{100} \)) x 44,000 = \( \frac{1,804,000}{100} \) = 18,040

The mayor got 79% of the votes cast which is:

(\( \frac{79}{100} \)) x 18,040 = \( \frac{1,425,160}{100} \) = 14,252 votes.


2

What is \( 3 \)\( \sqrt{80} \) + \( 7 \)\( \sqrt{5} \)

35% Answer Correctly
21\( \sqrt{16} \)
21\( \sqrt{80} \)
19\( \sqrt{5} \)
10\( \sqrt{5} \)

Solution

To add these radicals together their radicands must be the same:

3\( \sqrt{80} \) + 7\( \sqrt{5} \)
3\( \sqrt{16 \times 5} \) + 7\( \sqrt{5} \)
3\( \sqrt{4^2 \times 5} \) + 7\( \sqrt{5} \)
(3)(4)\( \sqrt{5} \) + 7\( \sqrt{5} \)
12\( \sqrt{5} \) + 7\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

12\( \sqrt{5} \) + 7\( \sqrt{5} \)
(12 + 7)\( \sqrt{5} \)
19\( \sqrt{5} \)


3

What is 3c6 - c6?

71% Answer Correctly
4c36
2c6
4c12
-2c-6

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

3c6 - 1c6
(3 - 1)c6
2c6


4

Monica scored 93% on her final exam. If each question was worth 4 points and there were 320 possible points on the exam, how many questions did Monica answer correctly?

57% Answer Correctly
74
60
66
70

Solution

Monica scored 93% on the test meaning she earned 93% of the possible points on the test. There were 320 possible points on the test so she earned 320 x 0.93 = 296 points. Each question is worth 4 points so she got \( \frac{296}{4} \) = 74 questions right.


5

What is \( 7 \)\( \sqrt{63} \) - \( 3 \)\( \sqrt{7} \)

38% Answer Correctly
21\( \sqrt{441} \)
4\( \sqrt{63} \)
18\( \sqrt{7} \)
21\( \sqrt{7} \)

Solution

To subtract these radicals together their radicands must be the same:

7\( \sqrt{63} \) - 3\( \sqrt{7} \)
7\( \sqrt{9 \times 7} \) - 3\( \sqrt{7} \)
7\( \sqrt{3^2 \times 7} \) - 3\( \sqrt{7} \)
(7)(3)\( \sqrt{7} \) - 3\( \sqrt{7} \)
21\( \sqrt{7} \) - 3\( \sqrt{7} \)

Now that the radicands are identical, you can subtract them:

21\( \sqrt{7} \) - 3\( \sqrt{7} \)
(21 - 3)\( \sqrt{7} \)
18\( \sqrt{7} \)